I'm assuming the question is time it will take for ball to reach ground, if it is then set equation to zero then use the quadratic formula, the possible t value is your answer then
Answer:
180.4 m
Explanation:
The package in relation to the point where it was released falls a certain distance that is calculated by applying the horizontal motion formulas , as the horizontal speed of the plane and the height above the ground are known, the time that It takes the package to reach its destination and then the horizontal distance (x) is calculated from where it was dropped, as follows:

h = 100 m
x =?
Height formula h:

Time t is cleared:


t = 4.51 sec
Horizontal distance formula x:

x = 40 m / sec x 4.51 sec
x = 180.4 m
Answer:
5 m
Explanation:
From the question,
v = λf....................... Equation 1
Where v = speed of the sound wave, λ = wavelength of the sound wave, f = frequency of the sound wave.
make λ the subject of the equation
λ = v/f..................... Equation 2
Given: v = 150 cm/s = 1.5 m/s, f = 0.3 hz.
Substitute these values into equation 2
λ = 1.5/0.3
λ = 5 m.
The electrical force between these two charges remains the
same. In coulomb’s law, it states that the magnitude of two charges (product of
two charges) is inversely proportional to the square of the distance. Since both
the magnitude and the distance are halved, therefore, the change in both quantities
will have no effect in the value of electrical force.
Answer:
A car accelerating to the right
Explanation:
The free-body diagram shows all the forces acting on an object. The length of each arrow is proportional to the magnitude of the force represented by that arrow.
In this free-body diagram, we see that there are 4 forces acting on the object, in 4 different directions. We also see that the two vertical forces are equal so they are balanced, while the force to the rigth is larger than the force to the left: this means that there is a net force to the right, so the object is accelerating to the right.
Therefore, the correct answer is:
A car accelerating to the right