Explanation:
The observation from the gold foil experiment by Rutherford was that, while most of the alpha particles went through the foil almost unaffected, a small fraction of the particles were deflected in directions with large angles away from the original path (including bouncing straight back). This was unexpected and led to a complete revision of the model (as relates to your part 1).
The nuclear model proposes a spacially small but massively charged nucleus. Due to its small size, most alpha particles will pass through the atoms of the gold foil unaffected (they "miss" the small nucleus). But some of them will come very close to the nucleus and those will be deflected strongly by its charge. This is one of the main arguments explaining the observation and speaking for the validity of the nuclear model.
Answer:
Explanation:
When 2 gms of steam condenses to water at 100 degree latent heat of vaporization is releases which is calculated as follows
Heat released = mass x latent heat of vaporization
= 2 x 2260 = 4520 J
When 2 gms of water at 100 degree is cooled to ice water at zero degree heat is releases which is calculated as follows
Heat released = mass x specific heat x( 100-0)
= 2 x 4.2 x 100 = 840 J
When 2 gms of water at zero degree condenses to ice at zero degree latent heat of fusion is releases which is calculated as follows
Heat released = mass x latent heat of fusion
= 2 x 334 = 668 J
When 2 grams of steam at 100 degrees Celsius turns to ice at 0 degrees Celsius heat released will be sum of all the heat released as mentioned above ie
4520 + 840 +668 = 6028 J
It will decrease in the same proportion.