Answer:
a) The change in potential energy of a 3.0 kilograms backpack carried up the stairs.
b) The change in potential energy of a persona with weight 650 newtons that descends the stairs is -2665 joules.
Explanation:
Let consider the bottom of the first floor in a building as the zero reference (
). The change in potential energy experimented by a particle (
), measured in joules, is:
(1)
Where:
- Mass, measured in kilograms.
- Gravitational acceleration, measured in meters per square second.
,
- Initial and final height with respect to zero reference, measured in meters.
Please notice that
is the weight of the particle, measured in newtons.
a) If we know that
,
,
and
, then the change in potential energy is:


The change in potential energy of a 3.0 kilograms backpack carried up the stairs.
b) If we know that
,
and
, then the change in potential energy is:


The change in potential energy of a persona with weight 650 newtons that descends the stairs is -2665 joules.