Question:
A chemistry student needs of 10 g isopropenylbenzene for an experiment. He has available 120 g of a 42.7% w/w solution of isopropenylbenzene in acetone. Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button.
Answer:
The answer to the question is as follows
The mass of solution the student should use is 23.42 g.
Explanation:
To solve the question we note the following
A solution containing 42.7 % w/w of isopropenylbenzene in acetone has 42.7 g of isopropenylbenzene in 100 grams of the solution
Therefore we have 10 g of isopropenylbenzene contained in
100 g * 10 g/ 42.7 g = 23.42 g of solution
Available solution = 120 g
Therefore the quantity to used from the available solution = 23.42 g of the isopropenylbenzene in acetone solution.
Answer:
4.52×10^24
Explanation:
N = n × Na
where; N = no. of bananas
n = no. of moles
Na = Avogadro's constant
Which is 6.02×10^23
N = 7.5 × 6.02×10^23
N =4.515×10^24
(1) Copper:
Copper has the atomic number : 29
Cu2+ means that it lost 2 electrons, therefore, the total number of electrons is 29-2 = 27 electrons.
The electronic configuration is:
1s2 2s2 2p6 3s2 3p6 3d9
(2) Silver:
Silver has atomic number : 47
Ag + means that it lost one electron, therefore, the total number of electrons is 47-1 = 46 electrons
The electronic configuration is:
<span>1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10</span>
Answer:
Explanation:
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