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2 years ago

A box with a mass of 2 kg accelerates in a straight line

Physics

1 answer:

mihalych1998 [28]2 years ago

7 0

Answer: 16N

Explanation:

Given that:

mass of box M= 2 kg

Initial speed V1 = 4 m/s

Final speed V2 = 8 m/s

Time taken T= 0.5 s

Average strength of this force F = ?

Now, recall that Force is the rate of change of momentum per unit time

i.e Force = momentum / time

Hence, F = M x (V2 - V1)/T

F = 2kg x (8 m/s - 4 m/s) / 0.5s

F = 2kg x (4 m/s / 0.5s)

F = 2kg x 8 m/s/s)

F = 16N

Thus, the average strength of this

force is 16 newton.

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A 50.0 kg driver is riding at 35.0 m/s in her red sports car when she must suddenly slam on the brakes to avoid

egoroff_w [7]

Answer:

3500N

Explanation:

Given parameters:

Mass of driver = 50kg

Speed = 35m/s

Time = 0.5s

Unknown:

Average force the seat belt exerts on her = ?

Solution:

The average force the seat belt exerts on her can be deduced from Newton's second law of motion.

F = mass x acceleration

So;

F = mass x $\frac{change in velocity }{time}$

F = 50 x $\frac{35}{0.5}$ = 3500N

8 0

3 years ago

A person throws a pumpkin at a horizontal speed of 4.0 — off a cliff. The pumpkin travels 9.5 m horizontally

emmainna [20.7K]

Complete Question

A person throws a pumpkin at a horizontal speed of 4.0 m/s off a cliff. The pumpkin travels 9.5m horizontally before it hits the ground. We can ignore air resistance.What is the pumpkin's vertical displacement during the throw? What is the pumpkin's vertical velocity when it hits the ground?

Answer:

The pumpkin's vertical displacement is $H = 27 .67 \ m$

The pumpkin's vertical velocity when it hits the ground is $v_v__{f}} = 23.298 \ m/s$

Explanation:

From the question we are told that

The horizontal speed is $v_h = 4 m/s$

The horizontal distance traveled is $d = 9.5 \ m$

The horizontal distance traveled is mathematically represented as

$S = v_h * t$

Where t is the time taken

substituting values

$9.5 = 4 * t$

=> $t = \frac{9.5}{4}$

$t = 2.38 \ sec$

Now the vertical displacement is mathematically represented as

$H = v_v t + \frac{1}{2} a_v t^2$

now the vertical velocity before the throw is zero

$H = 0 + \frac{1}{2} (9.8) * (2.375)^2$

$H = 27 .67 \ m$

Now the final vertical velocity is mathematically represented as

$v_v__{f}} = v_v + at$

substituting values

$v_v__{f}} = 0 + (9.8)* (2.375)$

$v_v__{f}} = 23.298 \ m/s$

7 0

2 years ago

A hiker walks 11 km due north from camp and then turns and walks 11 km due east. What is the magnitude of the displacement (on a

sattari [20]

Answer:

16 km

Explanation:

Drawing a right triangle to model the problem helps. I started by drawing the lines of the triangle to model the hiker's journey- a vertical straight line for 11 km north and then a horizontal line connected to the top of it for 11 km east; I then drew the hypothenuse to connect the two lines.

The hypothenuse is what we have to solve for, so we will use the Pythagorean Theorem, a^2 + b^2 = c^2. Since both distances are 11 km both a and b in the equation are 11.

11^2 + 11^2 = c^2

121 + 121 = c^2

242 = c^2

c = 15.56

Rounding the answer makes it 16 km for the hiker's magnitude of displacement.

5 0

3 years ago

What happened to an iron bar if it is heated from 32 degree Celsius to 64 degree Celsius

olganol [36]

Answer:

it got hotter

Explanation:

it just did

5 0

2 years ago

What is 7.325 NS x 10 to the 549 power GS equal?

Alexxandr [17]

Idrk sorry ___\........../.....

5 0

2 years ago