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gulaghasi [49]
3 years ago
11

A spaceship orbiting earth flies to the moon. How is the gravitational force pulling on the spaceship related to the distance th

at the spaceship is from the earth?
Question 25 options:

The gravitational pull of the earth is constant and therefore the gravitational pull on would not change.


As the distance from the earth decreases, the gravitational pull on the spaceship would decrease.


There is no gravity on the moon and therefore only the earth will exert gravitational force on the spaceship.


As the distance from the earth increases, the gravitational pull on the spaceship would decrease.
Physics
1 answer:
____ [38]3 years ago
3 0
The correct answer is "As the distance from the earth increases, the gravitational pull on the spaceship would decrease."

In fact, the gravitational force (attractive) exerted by the Earth on the spaceship is given by
F=G \frac{Mm}{d^2}
where G is the gravitational constant, M the Earth's mass, m the mass of the spaceship and d the distance of the spaceship from the Earth. As we can see from the formula, as the distance d between the spaceship and the Earth increases, the gravitational force F decreases, so answer D) is the correct one.
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A ball is hit so that it accelerates at 10 m/s2. The ball hits a glove with a force of 5 N. What is the mass of the ball?
jenyasd209 [6]

Answer:

0.5 kg

Explanation:

» <u>Concepts</u>

Newton's second law, the Law of Acceleration, states that F = ma, where F = Force in Newtons, m = mass in kg, and a = acceleration in m/s^2.

» <u>Application</u>

We are asked to find the mass of the ball using the equation F = ma. We're also given the force and acceleration, so the equation looks like 5 = 10(m).

» <u>Solution</u>

Step 1: Divide both sides by 10.

  • 5/10=10m/10
  • m=0.5

Thus, the mass of the ball is 0.5 kg.

8 0
2 years ago
The differential equation below models the temperature of an 88°C cup of coffee in a 24°C room, where it is known that the coffe
densk [106]

Answer:

y = 24+64\cdot e^{-150\cdot t}

Explanation:

Let solve the differential equation by separating corresponding variables:

\int\limits^t_0\, dt = -\frac{1}{150} \int\limits^y_{y_{o}} \frac{dy}{y-24}

The solution of this equation is:

t = -\frac{1}{150}\cdot (\ln|y-24|-\ln |y_{o}-24|)

The explicit form of the temperature as a function of time is:

\ln |y-24|=-150\cdot t + \ln |y_{o}-24|

y-24 = C\cdot e^{-150\cdot t}

The value of the integration constant is:

C = 64

The complete expression is:

y = 24+64\cdot e^{-150\cdot t}

3 0
3 years ago
Can someone please answer these in the next 20 minutes. ill give you a brainiest. thanks! :)
oee [108]

Answer:

1. 2380m

2. 13.6m

3. 132 Hz

6 0
3 years ago
Two loops of wire are arranged so that a changing current in one will induce a current in the other. If the current in the first
patriot [66]

Answer:

The current in the second loop will stay constant

Explanation:

Since the induced emf in the second coil, ε due to the changing current i₁ in the first wire loop ε = -Mdi₁/dt where M = mutual inductance of the coils and di₁/dt = rate of change of current in the first coil = + 1 A/s (positive since it is clockwise)

Now ε = i₂R where i₂ = current in second wire loop and R = resistance of second wire loop.

So,  i₂R = -Mdi₁/dt

i₂ = -Mdi₁/dt/R

Since di₁/dt = + 1 A/s,

i₂ = -Mdi₁/dt/R

i₂ = -M × + 1 A/s/R

i₂ = -M/R

Since M and R are constant, this implies that i₂ = constant

<u>So, the current in the second wire loop will stay constant.</u>

3 0
3 years ago
A car is travelling to the right with a speed of 42 m/s when the driver slams on the brakes the car skids 4.0 second
Tcecarenko [31]

Answer:

84m

Explanation:

4 0
3 years ago
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