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mojhsa [17]
2 years ago
12

Rock transfers heat rapidly.truefalse

Chemistry
1 answer:
MaRussiya [10]2 years ago
6 0
No, it does not. I believe it's false. 
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If an unknown sample contains 39.04% sulfuric acid by mass, then a 0.9368 g of that sample would require _____ mL of 0.2389 M Na
bonufazy [111]

Answer:

A) 31.22

Explanation:

The reaction of sulfuric acid with NaOH is:

H₂SO₄ + 2 NaOH → Na₂SO₄ + 2H₂O

To solve this problem we need to determine the moles of acid that will react, and, using the chemical equation we can determine the moles of NaOH and the volume that a 0.2389M NaOH solution would require to neutralize it.

<em>Moles H₂SO₄ (Molar mass: 98.08g/mol):</em>

0.9368g * 39.04% = 0.3657g H₂SO₄ * (1mol / 98.08g) =

3.7289x10⁻³moles H₂SO₄

And moles of NaOH that you require to neutralize the acid are:

3.7289x10⁻³moles H₂SO₄ * (2 moles NaOH / 1 mole H₂SO₄) =

7.4578x10⁻³ moles NaOH

Using a 0.2389M NaOH solution:

7.4578x10⁻³ moles NaOH * (1L / 0.2389mol) = 0.03122L = 31.22mL

Right answer is:

<h3>A) 31.22 </h3>

5 0
3 years ago
Which process of making a stainless steel product does the photograph
Delvig [45]
It would be B, combining
5 0
2 years ago
Read 2 more answers
BF3 + Li2SO3 ----&gt; B2(SO3)3 + LiF What is the coefficient of lithium fluoride in the balanced chemical reaction?
egoroff_w [7]
2BF₃ + 3Li₂SO₃ ----> B₂(SO₃)₃ + <u>6LiF

</u>:)<u>

</u>
6 0
3 years ago
Read 2 more answers
The diagram below shows a box with
Delicious77 [7]
The answer is: D the box will NOT move or change. Hope this helps!
5 0
3 years ago
When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 14.4 g of carbon were burned in the presence of
Yanka [14]

Answer:

Mass of carbon dioxide produced = 52.8 g

Explanation:

Given data:

Mass of carbon react = 14.4 g

Mass of oxygen = 56.5 g

Mass of oxygen left = 18.1 g

Mass of carbon dioxide produced = ?

Solution:

C + O₂     →      CO₂

Number of moles of C:

Number of moles = mass/ molar mass

Number of moles = 14.4 g/ 12 g/mol

Number of moles = 1.2 mol

18.1 g of oxygen left it means carbon is limiting reactant.

Now we will compare the moles of C with CO₂.

                       C             :         CO₂

                        1             :          1

                      1.2           :          1.2

Mass of CO₂:

Mass = number of moles × molar mass

Mass = 1.2  mol × 44 g/mol

Mass = 52.8 g

8 0
2 years ago
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