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Black_prince [1.1K]
3 years ago
14

What force is needed to give a 4.5-kg bowling ball an acceleration of 9 m/s2?

Physics
2 answers:
Sloan [31]3 years ago
8 0
F=ma  
f=4.5*9                                           

40.5 N
hope this help
topjm [15]3 years ago
7 0
What force is needed to give a 4.5-kg bowling ball an acceleration of 9 m/s2? 

F = ma

F = 4.5 x 9

40.5 N
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3 0
3 years ago
bumper car A (281 kg) moving +2.82 m/s makes an elastic collision with bumper car B (209 kg) moving +1.72 m/s what is the veloci
spin [16.1K]

Answer: V1 = 3.559 - 0.744V2

Explanation: Given that the

bumper car A has

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bumper car B has

Mass M2 = (209 kg) moving with

Velocity U2 = 1.72 m/s

Where U1, U2 are the initial velocity of the two cars

Since the collision is elastic, we will use the formula below,

M1U1 + M2U2 = M1V1 + M2V2

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640.68 + 359.48 = 281V1 + 209V2

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281V1 = 1000.16 - 209V2

V1 = 1000.16/281 - 209V2/281

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Therefore, the velocity of car A which

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6 0
3 years ago
How much heat is needed to raise the temperature of 7g of Water by 20° C
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A straight wire in a magnetic field experiences a force of 0.017 N when the current in the wire is 1.1 A. The current in the wir
mel-nik [20]

Answer:

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Given;

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the new current in the wire, I₂ = ?

Applying equation of magnetic force on conductor;

F₁ = I₁BLsinθ

F₂ = I₂BLsinθ

BLsinθ  = F₁/I₁ = F₂/I₂

I₂ = (F₂I₁)/F₁

I₂ = (0.077 x 1.1) / 0.017

I₂ = 4.98 A

Therefore, the new current in the straight wire is 4.98 A

3 0
3 years ago
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