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vovikov84 [41]
3 years ago
13

If a solution turns litmus paper turns red, which type of solution is it?

Chemistry
2 answers:
Olenka [21]3 years ago
8 0
An acid
A neutral solution will not change the litmus paper colour or it will change to green
And a base would change it blue. 
lukranit [14]3 years ago
6 0

Answer:

An acid solution.

Explanation:

The litmus paper is an acid-base indicator, its colors change depending on the pH of the solution. If the pH < 4.5, the litmus paper turns red, if the pH> 8.3 the litmus paper turns blue.

If the pH > 7, there is a base solution, if the pH< 7 there is an acid solution, and if the pH = 7 its a neutral solution.

So, if the litmus paper turned red, the solution has pH<4.5, and it's an acid solution.

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For each of the following pairs of compounds, name one absorption band that could be used to distinguish between them. CH3CH2OH
GrogVix [38]

Answer:

For CH3CH2OH the OH stretch between 3550-3200 cm-1

For CH3CH2NH2 a pair of bands at 3500 and 3400 cm-1 respectively corresponding to the N-H stretch

Explanation:

CH3CH2OH is ethanol. This is a primary alcohol characterized by the by the -OH (hydroxyl) group. A strong broad IR absorption in the 3550 - 3200 cm-1 corresponds to the O-H stretch and indicates that the compound could be an alcohol or it has an OH functional group.

CH3CH2NH2 is ethylamine. This is a primary amine characterized by the -NH2 (amino) group. The presence of a primary amine shows up as a pair of medium strength absorption features corresponding to the N-H stretch, one at around 3500 cm-1 and the other around 3400 cm-1.

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3 years ago
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A quantity of liquid methanol, CH3OH, is introduced intoa rigid 3.00-L vessel, the vessel is sealed, and the temperature israise
Tom [10]

Answer:

74,3 grams is the mass of methanol that was initially introduced into the vessel

Explanation:

                         CH3OH(g)        ---->          1 CO(g)    +   2 H2(g)

initial:             Idk what i have (X)                    -                    -

react:                initial - react                        react              react

equilibrium:    A concentration                  A conc.         0.426 M

                         in equilibrum                      in eq      

                         

See that in equilibrium are formed 2 moles of H2 with this concentration, 0,426M and you form 1 mol of CO, so the moles that are formed of H2 are the double of CO, because stoychiometry.

                            CH3OH(g)        ---->          1 CO(g)    +   2 H2(g)

initial:                 Idk what i have (X)                   -                    -

react:                    initial - react                     react              react

equilibrium:        A conc. in eq                     0,213 M         0.426 M

So we have concentrations of products in equilibrium, and we have Kc, now we can find concentration of reactants in equilibrium

Kc = ([CO] . [H2]*2) / [CH3OH]

6,9X10*-2 = (0,213 . 0,426*2) / [CH3OH]

[CH3OH] = (0,213 . 0,426*2) / 6,9X10*-2

[CH3OH] = 0,560 M

You know that 1 mol which reacted has this concentration in equilibrium, 0,213 M so I can know what's my initial concentration of reactive

Initial - react = equilibrium

initial - 0,213M = 0,560M ---> Initial = 0,773 M

0,773M is initial concentration of CH3OH, but this is molarity, (moles in 1L). My volume is 3 L so

1 L _____ 0,773 moles

3 L _____  3L . 0,773moles = 2,319 (the moles that i used)

Molar mass CH3OH = 32.06 g/m

Moles . molar mass = grams ---> 2,319 moles . 32,06 g/m  = 74,3 g                                                

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