Question

A 1.6-cm-thick wood floor covers a 4.0m×5.5m room. Part A The subfloor on which the flooring sits is at a temperature of 16.1 ∘C, while the air in the room is at 19.5 ∘C. What is the rate of heat conduction through the floor? Use 0.200 W/m⋅K for the thermal conductivity of wood.

Answer 1

Answer:

Rate of heat conduction will be 935 Watt

Explanation:

We have given thickness of the floor d = 1.6 cm = 0.016 m

Area $A=4\times 5.5=22m^2$

Temperature difference $\Delta T=19.5-16.1=3.4^{\circ}C$

Thermal conductivity of the wood k = 0.200 w/M-K

We have to find heat conduction

Heat conduction is given by $\frac{Q}{t}=\frac{kA\Delta T}{d}=\frac{0.200\times 22\times 3.4}{0.016}=935Watt$

Rate of heat conduction will be 935 Watt