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mr_godi [17]
4 years ago
8

One

Physics
1 answer:
Aleonysh [2.5K]4 years ago
3 0

Answer:

8.0 mm

Explanation:

Force of a spring is:

F = kx

where k is the spring constant and x is the displacement.

When the force is equal to Ben's weight:

mg = kx

(180 kg) (9.8 m/s²) = (220,000 N/m) x

x = 0.0080 m

The spring compresses 0.0080 m, or 8.0 mm.

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Radda [10]

Answer:

a)it increasing accelerates, constant acceleration, decreasing acceleration

b)6.66m/sec

Explanation:

b)speed=distance/time

7 0
3 years ago
2. If Peter is traveling .25 m/s on his bike, how long will it take him to reach
Semmy [17]

Answer:

48 seconds

Explanation:

Since S=d/t, plug in the known values and solve

0.25m/s=12m/t

0.25m/s*t=12m

t=12m/0.25m/s

t=48 seconds

7 0
3 years ago
Read 2 more answers
Will the velocity of a box change as it moves across the surface with no friction?Explain ​
nevsk [136]
The velocity will remain unchanged (Newton’s 1st Law) unless a force acts on it. If no friction force, then the velocity remains constant.
3 0
3 years ago
A 58.0-kg projectile is fired at an angle of 30.0° above the horizontal with an initial speed of 140 m/s from the top of a cliff
strojnjashka [21]

(a) 6.43\cdot 10^5 J

The total mechanical energy of the projectile at the beginning is the sum of the initial kinetic energy (K) and potential energy (U):

E=K+U

The initial kinetic energy is:

K=\frac{1}{2}mv^2

where m = 58.0 kg is the mass of the projectile and v=140 m/s is the initial speed. Substituting,

K=\frac{1}{2}(58 kg)(140 m/s)^2=5.68\cdot 10^5 J

The initial potential energy is given by

U=mgh

where g=9.8 m/s^2 is the gravitational acceleration and h=132 m is the height of the cliff. Substituting,

U=(58.0 kg)(9.8 m/s^2)(132 m)=7.5\cdot 10^4 J

So, the initial mechanical energy is

E=K+U=5.68\cdot 10^5 J+7.5\cdot 10^4 J=6.43\cdot 10^5 J

(b) -1.67 \cdot 10^5 J

We need to calculate the total mechanical energy of the projectile when it reaches its maximum height of y=336 m, where it is travelling at a speed of v=99.2 m/s.

The kinetic energy is

K=\frac{1}{2}(58 kg)(99.2 m/s)^2=2.85\cdot 10^5 J

while the potential energy is

U=(58.0 kg)(9.8 m/s^2)(336 m)=1.91\cdot 10^5 J

So, the mechanical energy is

E=K+U=2.85\cdot 10^5 J+1.91 \cdot 10^5 J=4.76\cdot 10^5 J

And the work done by friction is equal to the difference between the initial mechanical energy of the projectile, and the new mechanical energy:

W=E_f-E_i=4.76\cdot 10^5 J-6.43\cdot 10^5 J=-1.67 \cdot 10^5 J

And the work is negative because air friction is opposite to the direction of motion of the projectile.

(c) 88.1 m/s

The work done by air friction when the projectile goes down is one and a half times (which means 1.5 times) the work done when it is going up, so:

W=(1.5)(-1.67\cdot 10^5 J)=-2.51\cdot 10^5 J

When the projectile hits the ground, its potential energy is zero, because the heigth is zero: h=0, U=0. So, the projectile has only kinetic energy:

E = K

The final mechanical energy of the projectile will be the mechanical energy at the point of maximum height plus the work done by friction:

E_f = E_h + W=4.76\cdot 10^5 J +(-2.51\cdot 10^5 J)=2.25\cdot 10^5 J

And this is only kinetic energy:

E=K=\frac{1}{2}mv^2

So, we can solve to find the final speed:

v=\sqrt{\frac{2E}{m}}=\sqrt{\frac{2(2.25\cdot 10^5 J)}{58 kg}}=88.1 m/s

4 0
3 years ago
A car brakes from 25 m/s to 16 m/s in 2.0s. what is its acceleration?<br>​
Mars2501 [29]
Acceleration = (16-25) / 2 = - 4.5 m/s^2
3 0
3 years ago
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