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3 years ago

WHAT IS AN Ionic bond

Chemistry

2 answers:

Snezhnost [94]3 years ago

7 0

Answer:

An ionic bond is a chemical bond that results from electrostatic attraction between positive and negative ions.

Explanation:

It occurs between a metal and a non-metal, and the electronegativity will always be greater than 1.7 (which are both expedient ways of identifying this type of reaction). I hope this helps!

lidiya [134]3 years ago

6 0

${\orange { \mathbb{ \huge{QUESTION}}}}$

WHAT IS AN IONIC BOND

$\huge\boxed{\fcolorbox{red}{blue}{ ANSWER }}$

$\orange{\underline{\huge{\bold{\textit{\green{\bf{Ionic \:Bond}}}}}}}$

kossel explained that inert gases r inert due to the electronic configuration which contains 8 electrons in their outermost shell

And other elements loss and gain electrons to form ions and to have electronic configuration same as Noble gas and to get stable

$Hope\: it \:is\: helpful$

$Mark \:as\: the\: brainlist\: ans\: with \:thanks...$

#SARDAR JI.

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A solution of phosphoric acid was made by dissolving 10.8 g of H3PO4 in 133.00 mL of water. The resulting volume was 137 mL. Cal

Nesterboy [21]

Answer:

Density is: 1.05 g/ml

Mole fraction solute: 0.015

Mole fraction solvent: 0.095

Molarity: 0.80 M

Molality: 0.82 m

Explanation:

A typical excersise of solution.

It is more confortable to make a table for this.

| masss | volume | mol

solute | | |

solvent | | |

solution | | |

Let's complete, what we have.

| masss | volume | mol

solute | 10.8g | |

solvent | | 133 mL |

solution | | 137 mL |

We can first, know how many moles are 10.8 g

Molar Mass H3PO4 = 97.99 g/mol

Mass / Molar mass = mol

10.8 g / 97.99 g/m = 0.110 mol

Density of water is 1 g/ml (it is a very knowly value)

From this data, we can know water mass, solvent.

Density = mass / volume

1 g/ml = mass / 133 mL

Mass = 133 g

We can also have the moles, by the molar mass of water 18 g/m

133 g / 18 g/m = 7.39 mol

| masss | volume | mol

solute | 10.8g | | 0.110 mol

solvent | 133g | 133 mL | 7.39 mol

solution | 143.8g | 137 mL | 7.50 mol

Mass of solution will be solute mass + solvent mass

Moles of solution will be solute moles + solvent moles

Now we can calculate everything.

Molarity means mol of solute in 1 L of solution. (mol/L)

We have to convert 137 mL in L (/1000)

0.137L so → 0.110 m / 0.137L = 0.80 M

Molality means mol of solute in 1kg of solvent.

We have to convert 133g in kg (/1000)

0.133 kg so → 0.110 m/0.133 kg = 0.82 m

Density is mass / volume

Solution density will be solution mass / solution volume

143.8 g/137 mL = 1.05 g/m

Molar fraction is : solute moles / total moles or solvent moles/total moles.

You can also (x 100%) to have a percent of them.

Remember sum of molar fraction = 1

Molar fraction of solute = 0.110 mol / 7.50mol = 0.015

Molar fraction of solvent = 7.39 mol / 7.50 mol = 0.985

5 0

3 years ago

In humans, genetic material in the cell is organized into

vladimir2022 [97]

23 pairs of chromosomes, since there is 46 singular chromosomes.

6 0

3 years ago

Gaseous ICl (0.20 mol) was added to a 2.0 L flask and allowed to decompose at a high temperature:

Ne4ueva [31]

Answer:

The Kc is 1.36 (but this is not an option, may be the options are wrong, or may be I was .. Thanks!)

Explanation:

Let's think all the situation.

2 ICl(g) ⇄ I₂(g) + Cl₂(g)

Initially 0.20 - -

Initially I have only 0.20 moles of reactant, and nothing of products. In the reaction, an x amount of compound has reacted.

React x x/2 x/2

Because the ratio is 2:1, in the reaction I have the half of moles.

So in equilibrium I will have

(0.20 - x) x/2 x/2

Notice that I have the concentration in equilibrium so:

0.20 - x = 0.060

x = 0.14

So in equilibrium I have formed 0.14/2 moles of I₂ and H₂ (0.07 moles)

Finally, we have to make, the expression for Kc and remember that must to be with concentration in M (mol/L).

As we have a volume of 2L, the values must be /2

Kc = ([I₂]/2 . [H₂]/2) / ([ICl]/2)²

Kc = (0.07/2 . 0.07/2) / (0.060/2)²

Kc = 1.225x10⁻³ / 9x10⁻⁴

Kc = 1.36

8 0

3 years ago

When aqueous solutions of manganese(II) iodide and sodium phosphate are combined, solid manganese(II) phosphate and a solution o

Feliz [49]

Answer:

The net ionic equation for the given reaction :

$3Mn^{2+}(aq)+2PO_4^{3-}(aq)\rightarrow Mn_3(PO_4)_2(s)$

Explanation:

$3MnI_2(aq)+2Na_3PO_4_2(aq)\rightarrow Mn_3(PO_4)_2(s)+6NaI(aq)$ ...[1]

$MnI_2(aq)\rightarrow Mn^{2+}(aq)+2I^-(aq)$ ..[2]

$Na_3PO_4(aq)\rightarrow 3Na^{+}(aq)+PO_4^{3-}(aq)$ ...[3]

$NaI(aq)\rightarrow Na^+(aq)+I^-(aq)$

Replacing $MnI_2(aq)$ , NaI and $Na_3PO_4(aq)$ in [1] by usig [2] [3] and [4]

$3Mn^{2+}(aq)+6I^-(aq)+6Na^{+}(aq)+2PO_4^{3-}(aq)\rightarrow Mn_3(PO_4)_2(s)+6Na^+(aq)+6I^-(aq)$

Removing the common ions present ion both the sides, we get the net ionic equation for the given reaction [1]:

$3Mn^{2+}(aq)+2PO_4^{3-}(aq)\rightarrow Mn_3(PO_4)_2(s)$

8 0

3 years ago

Identify each statement as true or false. Explain in every case.a.Ionization energies are always negative quantities.b.Oxygen ha

worty [1.4K]

Answer:

(a) FALSE

(b) FALSE

(d) FALSE

Explanation:

Ionization energy refers to the energy needed for removal of a valence electron present in valence shell of a gaseous atom.

(a) The value of ionization energy of an atom is always positive. This is because energy has to be always supplied or provided to a gaseous atom for the removal of the valence electron.

Therefore, the statement (A) is false

(b) The ionization energy of an atom increases across a period i.e. from left to right. This is because the effective nuclear charge that is experienced by the valence electron increases from left to right in the periodic table, as the atomic number increases.

So, more energy is required to remove the valence electron of fluorine as compared to oxygen.

Therefore, the ionization energy of fluorine is greater than oxygen.

Therefore, the statement (B) is false

(c) First ionization energy is energy needed for removal of first electron present in valence shell of a neutral atom. Whereas, second ionization energy is the energy needed for removal of second electron present in valence shell of a monovalent cation

The second ionization energy of an atom is always greater than the first ionization energy. This is because removing an electron from a positively charged species, requires more energy.

Therefore, the statement (C) is true

(d) The third ionization energy refers to the energy needed to remove the third electron from a divalent cation.

Therefore, the statement (D) is false

7 0

3 years ago

WHAT IS AN Ionic bond​

WHAT IS AN Ionic bond