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3 years ago

Match each gas law with the correct statement.

Chemistry

2 answers:

ehidna [41]3 years ago

5 0

Answer:

Boyle's Law is B

Charles's Law is C

Gay-Lussac's Law is A

Explanation:

The reason these are correct is because:

Boyle's law is a indirect between pressure and volume

Charles's Law is direct between volume and temperature

Gay-Lussac's Law is direct pressure and temperature

Serhud [2]3 years ago

4 0

The correct match are as follows:

Boyles Law is about a gas at constant temperature. Therefore, the correct match would be the volume of a gas varies inversely with pressure if the temperature is kept constant.

Charles Law would be that the volume of a gas varies directly with temperature if the pressure is kept constant.

Gay-lussac's law would be that the pressure of a gas varies directly with temperature if the volume is kept constant.

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A chemist measures the amount of hydrogen gas produced during an experiment. She finds that 264. g of hydrogen gas is produced.

Lesechka [4]

Answer:

The answer is 130.953 g of hydrogen gas.

Explanation:

Hydrogen gas is formed by two atoms of hydrogen (H), so its molecular formula is H₂. We can calculate is molecular weight as the product of the molar mass of H (1.008 g/mol):

Molecular weight H₂= molar mass of H x 2= 1.008 g/mol x 2= 2.01568 g

Finally, we obtain the number of mol of H₂ there is in the produced gas mass (264 g) by using the molecular weight as follows:

mass= 264 g x 1 mol H₂/2.01568 g= 130.9731703 g

The final mass rounded to 3 significant digits is 130.973 g

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3 years ago

Einstein's formula tells us the amount of energy to which a given mass would be equivalent, if it were all suddenly turned into

skad [1K]

Einstein's famous equation, E = mc^2 relates the mass (m) of an object to energy (E). The speed of light (c), is the constant of proportionality. Einstein formulated the equation within his theory of special relativity. Indeed, a physical interpretation of this equation is that any given mass is equivalent to the energy given by the equation, if it were suddenly converted to energy. Therefore the answer to the question is true.

5 0

4 years ago

Q3 - Complete the word equation *

tia_tia [17]

Whoever gave u this homework, doesnt really understand the concept

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3 years ago

What is the final pH of a solution with an initial concentration of 2.5mM Ascorbic acid (H2C6H6O6) which has the following Kas:

riadik2000 [5.3K]

Answer:

pH = 3.39

Explanation:

The equilibrium in water of ascorbic acid (With its conjugate base) is:

H₂C₆H₆O₆(aq) + H₂O(l) ⇄ HC₆H₆O₆⁻(aq) + H₃O⁺(aq)

<em>Where the acidic dissociation constant is written as:</em>

Ka = 7.9x10⁻⁵ = [HC₆H₆O₆⁻] [H₃O⁺] / [H₂C₆H₆O₆]

H₂O is not taken in the Ka expression because is a pure liquid.

As initial concentration of H₂C₆H₆O₆ is 2.5x10⁻³M, the equilibrium concentration of each species in the equilibrium is:

[H₂C₆H₆O₆] = 2.5x10⁻³M - X

[HC₆H₆O₆⁻] = X

[H₃O⁺] = X

Replacing in the Ka expression:

7.9x10⁻⁵ = [X] [X] / [2.5x10⁻³M - X]

1.975x10⁻⁷ - 7.9x10⁻⁵X = X²

Solving for X:

X = -0.00048566→ False solution, there is no negative concentrations

X = 0.00040666 → Right solution

As [H₃O⁺] = X, [H₃O⁺] = 0.00040666

pH is defined as -log [H₃O⁺];

pH = -log 0.00040666,

5 0

3 years ago

An incompressible Newtonian fluid is brought to flow in a pipe by pulling a wire in the center at a velocity of 18 cm/s. The wir

weqwewe [10]

Answer:

The shear stress is 2.16 Pa

Explanation:

Newton's law of viscosity can be expressed as follows;

$\tau =\mu \times \dfrac{dv}{dy}$

Where:

τ = Shear stress in the fluid

Given that the diameter of the wire = 5 cm

The velocity of the wire = 18 cm/s

The diameter of the pipe = 10 cm

The fluid viscosity, μ = 3.0 cp = 1×10⁻³· Pa·s

The change in velocity from the surface of the wire to the internal surface of the pipe = dv = 18 cm/s

The change in the y (perpendicular) direction of motion of the fluid from the surface of the wire to the interior surface of the tube = dy = 10/2 - 5/2 = 2.5 cm

By putting in the values, we have;

$\tau =0.3 \times \dfrac{18}{2.5} = 2.16 \ Pa$

The shear stress = 2.16 Pa

7 0

3 years ago