How does the energy of an electorn change when the electron moves closer to the nucleus?

siniylev [52]

Answer:

The correct answer is "They can be separated by physical processes"

Explanation:

The definition of Mixtures is <em>the blending of two or more dissimilar substances</em>.

Mixtures can be divided into those that are homogeneous or heterogeneous meaning that they can be distributed evenly or can't be distributed evenly.

6 0

3 years ago

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Sometimes reactions to prices in oligopolistic markets can result in _________

STatiana [176]

Answer:

a price war

Explanation:

An Oligopoly is when a small group of two or more companies dominates a market. Oligopoly firms may consent to market collusion, and create barriers to new commerce entry. If the businesses do not, they will probably be forced to lower their prices and open the market to new and smaller companies.

It is the type of competition between the company selling the similar type of product , or rival companies who tries to reduce the price of the product strategizing in a way to apprehend the wider area of the market , is known as a price war .

In the event one of the firms forming the oligopoly decides to lower prices, a price war occurs breaking the balance of the oligopoly and destabilizing the equilibrium of demand and supply in that market.

Reduction of the price of any goods or commodity is considered to be one of the best method to increase its market share ,because as soon as the price of any good decreases , the sales automatically increases , as the consumers are always in search of some discounts and good deals .

price war -

7 0

3 years ago

The unit used to measure barometric or air pressure

Bumek [7]

Answer:

A barometer is an instrument used to measure air pressure and track weather systems. The most common unit of measurement used in barometers is the millibar (mb).

Explanation:

7 0

3 years ago

In the process of eukaryotic pre-mRNA splicing, how is the lariat intermediate formed?

Aleks [24]

Answer:

C

Explanation:

The Eukaryotic pre-mRNA receives a 5' cap and 3'poly(A) tail before Introns are removed and the mRNA is considered ready for translation.

4 0

2 years ago

A 17.11 gram sample of an organic compound containing only C, H, and O is analyzed by combustion analysis and 21.71 g CO2 and 5.

Andru [333]

Answer: The empirical formula and the molecular formula of the organic compound is $CHO$ and $C_4H_4O_4$ respectively.

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

$C_xH_yO_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2$ = 21.71 g

Mass of $H_2O$ = 5.926 g

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 21.71 g of carbon dioxide, = $\frac{12}{44}\times 21.71=5.921g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 5.926 g of water, = $\frac{2}{18}\times 5.926=0.658g$ of hydrogen will be contained.

Mass of oxygen in the compound = (17.11) - (5.921+0.658) = 10.53 g

Mass of C = 5.921 g

Mass of H = 0.658 g

Mass of O = 10.53 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{5.921g}{12g/mole}=0.493moles$

Moles of H= $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.658g}{1g/mole}=0.658moles$

Mass of O= $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{10.53g}{16g/mole}=0.658moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{0.493}{0.493}=1$

For H = $\frac{0.658}{0.493}=1$

For O= $\frac{0.658}{0.493}=1$

The ratio of C : H: O = 1: 1: 1

Hence the empirical formula is $CHO$ .

empirical mass of CHO = 12(1) + 1(1) + 1 (16) = 29

Molecular mass = 104.1 g/mol

$n=\frac{\text {Molecular mass}}{\text {Equivalent mass}}=\frac{104.1}{29}=4$

Thus molecular formula = $n\times {\text {Empirical formula}}=4\times CHO=C_4H_4O_4$

6 0

2 years ago