The thermal decomposition of calcium carbonate will produce 14 g of calcium oxide. The stoichiometric ratio of calcium carbonate to calcium oxide is 1:1, therefore the number of moles of calcium carbonate decomposed is equal to the number of moles of calcium oxide formed.
Further Explanation:
To solve this problem, follow the steps below:
- Write the balanced chemical equation for the given reaction.
- Convert the mass of calcium carbonate into moles.
- Determine the number of moles of calcium oxide formed by using the stoichiometric ratio for calcium oxide and calcium carbonate based on the coefficient of the chemical equation.
- Convert the number of moles of calcium oxide into mass.
Solving the given problem using the steps above:
STEP 1: The balanced chemical equation for the given reaction is:

STEP 2: Convert the mass of calcium carbonate into moles using the molar mass of calcium carbonate.

STEP 3: Use the stoichiometric ratio to determine the number of moles of CaO formed.
For every mole of calcium carbonate decomposed, one more of a calcium oxide is formed. Therefore,

STEP 4: Convert the moles of CaO into mass of CaO using its molar mass.

Since there are only 2 significant figures in the given, the final answer must have the same number of significant figures.
Therefore,

Learn More
- Learn more about stoichiometry brainly.com/question/12979299
- Learn more about mole conversion brainly.com/question/12972204
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Keywords: thermal decomposition, stoichiometry
Answer:
i think its B but im not so sure
Answer:

Explanation:
Na₂S₂O₃ solution does not react with KI (it reacts with I₂), so it is simply diluting the KI, and we can use the dilution formula.

Data:
c₁ = 0.15 mol·L⁻¹; V₁ = 5 drops
V(Na₂S₂O₃) = 40 drops
Calculations:
(a) Calculate the total volume
V₂ = 5 + 40 = 45 drops
(b) Calculate the concentration
0.15 × 5 = c₂ × 45
0.75 = 45c₂

The correct answer to the question is 25 percent by mass
Answer:
C.
Explanation:
MoleculesHcl = (1 molMgO/1)(2molHCL/1molMGO)(6.02x10^23/1molHCL) = 1.204x10^24