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Semmy [17]
3 years ago
9

Does the density of aluminum ever change?

Physics
1 answer:
Kamila [148]3 years ago
8 0

As long as the aluminum is pure, then the density cannot change. Aluminum is an element, and density is an identifying factor for elements because it is based on the atomic structure of the material. If you created an aluminum compound like aluminum oxide, then the density would be different


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How much work is done when a 5 N force moves a block 4 m?
katen-ka-za [31]
20N•m or 20J. Work is equal to force•distance, and 5N•4m is 20N•m, or J
4 0
3 years ago
Why does the number of dwarf planets recognized by astronomers in the solar system sometimes increase?
gregori [183]
Because sometimes it happens that they discover a dwarf planet
that nobody ever knew about before.  When that happens, they
ADD the new one to the list of known dwarf planets, and then the
total number of dwarf planets on the list increases by 1 .
4 0
3 years ago
A 912-kg car is being driven down a straight, level road at a constant speed of 31.5 m/s. When the driver sees a police cruiser
sergejj [24]

Answer:

786.6 N

Explanation:

mass of car, m = 912 kg

initial velocity of car, u = 31.5 m/s

final velocity of car, v = 24.6 m/ s

time, t = 8 s

Let a be the acceleration of the car

Use first equation of motion

v = u + a t

24.6 = 31.5 + a x 8

a = - 0.8625 m/s^2

Force, F = mass x acceleration

F = 912 x 0.8625

F = 786.6 N

Thus, the force on the car is 786.6 N.

8 0
2 years ago
A 30-gram bullet is fired and a 50-gram bullet is dropped simultaneously from the same height. Which will hit the ground first?
Marina86 [1]

Answer: the 30gram will hit the ground first

Explanation:the 30gram bullet will hit the ground first because it is fired

4 0
3 years ago
Read 2 more answers
A jet accelerates from rest down a runway at 1.75m/s² for a distance of 1500 m before takeoff.
babunello [35]
A. Using the third equation of motion:
v2 = u2 + 2as
from the question;
the jet was initially at rest
hence u = 0
a = 1.75m/s2
s = 1500m
v2 = 02 + 2(1.75)(1500)
v2 = 5250
v = √5250
v = 72.46m/s
hence it moves with a velocity of 72.46m/s.
b. s = ut + 1/2at2
1500 = 0(t) + 1/2(1.75)t2
1500 × 2 = 2× 1/2(1.75)t2
3000 = 1.75t2
1714.29 = t2
41.4 = t
hence the time taken for the plane to down the runway is 41.4s.


Read more on Brainly.com - brainly.com/question/18743384#readmore
8 0
3 years ago
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