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Svetradugi [14.3K]
4 years ago
5

What word is used to describe an acid or base that can destroy body tissue, clothing, and many other?

Physics
1 answer:
lara31 [8.8K]4 years ago
7 0

Corrosive. It’s something that tends to cause corrosion, and it means to destroy or damage things slowly by chemical action.

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If the mass of a material is 122 grams and the volume of the material is 10 cm3, what would the density of the material be?
sergij07 [2.7K]
<span>Since d=m/v. 122 g (mass) divided by 10 cm3 (volume)=</span>12.2 g/cm<span>3
Your answer would be 12.2 g/cm3
</span>
3 0
4 years ago
Which statement best define energy
Ksju [112]

Answer:

"The capacity of a system to perform work of any type."

Explanation:

The best statement to describe Energy is:

"The capacity of a system to perform work of any type."

6 0
4 years ago
An object is moving with constant speed in a
tankabanditka [31]

Answer:

both magnitude and direction

Explanation:

When an object moves in a circular path, its motion is called uniform circular motion. In this motion, the force acting on it is centripetal force and it is moving under centripetal acceleration. This type of force acts towards the centre of the circle.

In this type of motion, the speed remains constant while the velocity keeps on changing. The object's centripetal  acceleration remains constant in magnitude as well as direction.

Hence, the correct option is (3).

7 0
3 years ago
Performs Parts 1-3 in lab, Part 4 you answer by using your information gathered through Parts 1-3.
elena55 [62]
Oh okie oh gosh lol lol
5 0
3 years ago
Alan starts from his home and walks 1.3 km east to the library. He walks an additional 0.68 km east to a music store. From there
zepelin [54]

Answer: final Displacement = 0 km, total distance covered =7 km

Explanation:

Given the following :

From home to library = 1.3 km East

Library to music store = 0.68km East

Music store to friend's house = 1.1km North

Friend's house to grocery store = 0.42 km North

Displacement is the net change in distance traveled.

Eastward distance :

To = (1.3 + 0.68)km = 1.98km East

Fro = (0.68 + 1.3)km = 1.98 km East

Δ distance = (1.98 - 1.98) = 0

Northward direction:

To = (1.1 + 0.42)km = 1.52km north

Fro = (0.42 + 1.1)km = 1.52km North

Δ distance = (1.98 - 1.98) = 0

Hence final Displacement = 0

Total distance covered = 2 × (1.3 + 0.68 + 1.1 + 0.42) = 2 × 3.5

= 7km

3 0
4 years ago
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