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Inessa [10]
3 years ago
15

Suppose water waves are moving from the deep end to the shallow end of the pool. That is, the waves are moving into a medium (sh

allow water) where they slow down. In what direction will the waves turn slightly, and why
Physics
2 answers:
MissTica3 years ago
8 0

Answer:

The waves will turn slightly to the <em><u>left .</u></em>

Explanation :

The waves will turn slightly to the left, because the left side of each wave front hits the boundary first and slows down, moving more slowly than the right side until the right side of the wave front reaches the boundary. THis causes the wave to veer slightly to the left.

  Basically the speed of water depends upon depth of the river or the ocean.

the formula is as follows :

            v =  √gxd

           v =  √d               (g is the gravitational acceleration)

As the water waves are more at the deeper end then the shallow end, so during its course to the shallower end, they are slightly deviated toward the normal., hence it will move slightly to the left.

koban [17]3 years ago
8 0

Answer:

The wave turn slightly to the bottom.

Explanation: Because part of the wave travel faster causing the wave to turn.

If the wave is moving from deep to shallow, as the depth approaches 1/2 a wavelength, things start to change - the wave will start to rise vertically and eventually brake. You can imagine the bottom of the wave hitting the sea bottom and slowing down, the frequency will go up, the velocity of the wave will go down.

As a wave moves into shallow water, its orbitals “feel the bottom,” causing it to slow down. This end is in shallower water, so it slows down towards the shore than the slower-moving end in.

Water waves will change direction at a boundary between deep and shallowwater. The waves slow down as they enter the shallow water which causes the wavelengths to shorten.

As waves travel into the denser medium, they slow down and wavelength decreases.Part of the wave travels faster for longer causing the wave to turn.The wave is slower but the wavelength is shorter meaning frequency remains the same.

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Calculate the lowest energy (in ev) for an electron in an infinite well having a width of 0.050 mm.
MA_775_DIABLO [31]

The lowest energy of electron in an infinite well is 1.2*10^-33J.

To find the answer, we have to know more about the infinite well.

<h3>What is the lowest energy of electron in an infinite well?</h3>
  • It is given that, the infinite well having a width of 0.050 mm.
  • We have the expression for energy of electron in an infinite well as,

                  E_n=\frac{n^2h^2}{8mL^2}

  • where;

                m=9.1*10^{-31}kg\\L=0.050*10^{-3}m\\h=6.63*10^{-34}Js\\n=1

  • Thus, the lowest energy of electron in an infinite well is,

                E_1=\frac{(6.63*10^{-34})^2}{8*9.1*10^{-31}*(0.050*10^{-3})}=1.2*10^{-33}J

Thus, we can conclude that, the lowest energy of electron in an infinite well is 1.2*10^-33J.

Learn more about the infinite well here:

brainly.com/question/20317353

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7 0
1 year ago
If you stood on a planet with four times the mass of Earth, and twice Earth's radius, how much would you weigh?
nikdorinn [45]

Answer:

1/4 times your earth's weight

Explanation:

assuming the Mass of earth = M

Radius of earth = R

∴ the mass of the planet= 4M

the radius of the planet = 4R

gravitational force of earth is given as = \frac{GM}{R^{2} }

where G is the gravitational constant

Gravitational force of the planet = \frac{G4M}{(4R)^{2} }

                                                       =\frac{G4M}{16R^{2} }

                                                       =\frac{GM}{4R^{2} }

recall, gravitational force of earth is given as = \frac{GM}{R^{2} }

∴Gravitational force of planet = 1/4 times the gravitational force of the earth

you would weigh 1/4 times your earth's weight

3 0
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