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Inessa [10]
3 years ago
15

Suppose water waves are moving from the deep end to the shallow end of the pool. That is, the waves are moving into a medium (sh

allow water) where they slow down. In what direction will the waves turn slightly, and why
Physics
2 answers:
MissTica3 years ago
8 0

Answer:

The waves will turn slightly to the <em><u>left .</u></em>

Explanation :

The waves will turn slightly to the left, because the left side of each wave front hits the boundary first and slows down, moving more slowly than the right side until the right side of the wave front reaches the boundary. THis causes the wave to veer slightly to the left.

  Basically the speed of water depends upon depth of the river or the ocean.

the formula is as follows :

            v =  √gxd

           v =  √d               (g is the gravitational acceleration)

As the water waves are more at the deeper end then the shallow end, so during its course to the shallower end, they are slightly deviated toward the normal., hence it will move slightly to the left.

koban [17]3 years ago
8 0

Answer:

The wave turn slightly to the bottom.

Explanation: Because part of the wave travel faster causing the wave to turn.

If the wave is moving from deep to shallow, as the depth approaches 1/2 a wavelength, things start to change - the wave will start to rise vertically and eventually brake. You can imagine the bottom of the wave hitting the sea bottom and slowing down, the frequency will go up, the velocity of the wave will go down.

As a wave moves into shallow water, its orbitals “feel the bottom,” causing it to slow down. This end is in shallower water, so it slows down towards the shore than the slower-moving end in.

Water waves will change direction at a boundary between deep and shallowwater. The waves slow down as they enter the shallow water which causes the wavelengths to shorten.

As waves travel into the denser medium, they slow down and wavelength decreases.Part of the wave travels faster for longer causing the wave to turn.The wave is slower but the wavelength is shorter meaning frequency remains the same.

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3 years ago
Some people today claim the Earth is flat. Produce an argument to prove that the
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Is being social media famous worth real-life relationships?
Maru [420]

Answer:

No

Explanation:

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3 0
3 years ago
A 3.15-kg object is moving in a plane, with its x and y coordinates given by x = 6t2 − 4 and y = 5t3 + 6, where x and y are in m
ArbitrLikvidat [17]

Answer:

<h2>206.67N</h2>

Explanation:

The sum of force along both components x and y is expressed as;

\sum Fx = ma_x  \ and \ \sum Fy = ma_y

The magnitude of the net force which is also known as the resultant will be expressed as R =\sqrt{(\sum Fx)^2 + (\sum Fx )^2}

To get the resultant, we need to get the sum of the forces along each components. But first lets get the acceleration along the components first.

Given the position of the object along the x-component to be x = 6t² − 4;

a_x = \frac{d^2 x }{dt^2}

a_x = \frac{d}{dt}(\frac{dx}{dt} )\\ \\a_x = \frac{d}{dt}(6t^{2}-4  )\\\\a_x = \frac{d}{dt}(12t  )\\\\a_x = 12m/s^{2}

Similarly,

a_y = \frac{d}{dt}(\frac{dy}{dt} )\\ \\a_y = \frac{d}{dt}(5t^{3} +6 )\\\\a_y = \frac{d}{dt}(15t^{2}   )\\\\a_y = 30t\\a_y \ at \ t= 2.15s; a_y = 30(2.15)\\a_y = 64.5m/s^2

\sum F_x = 3.15 * 12 = 37.8N\\\sum F_y = 3.15 * 64.5 = 203.18N

R = \sqrt{37.8^2+203.18^2}\\ \\R = \sqrt{1428.84+41,282.11}\\ \\R = \sqrt{42.710.95}\\ \\R = 206.67N

Hence, the magnitude of the net force acting on this object at t = 2.15 s is approximately 206.67N

7 0
3 years ago
The Hubble Space Telescope has an aperture of 2.4 m and focuses visible light (400-700 nm). The Arecibo radio telescope in Puert
stealth61 [152]

Answer:

y_{hubble} = 77\ \ m

y_{aceribo} = 1.1*10^6 \ \ m

Explanation:

what is the smallest crater that each of these telescopes could resolve on our moon?

For moon ;

s = 3.8 × 10 ⁸ m

y = 1.22 λs/D

where;

λ = 400 nm = 400× 10 ⁻⁹

D = 2.4 m

The smallest crater for the hubble space is calculated as follows:

y_{hubble} = 1.22*400*10^{-9}*3.8*10^8/2.4

y_{hubble} = 77\ \ m

For Aceribo ;

y = 1.22 λs/D

where :

λ = 75 cm = 0.75 m

D = 305 m

y_{acerbo} = 1.22*0.75 *3.8*10^8/305

y_{aceribo} = 1.1*10^6 \ \ m

5 0
3 years ago
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