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Inessa [10]
3 years ago
15

Suppose water waves are moving from the deep end to the shallow end of the pool. That is, the waves are moving into a medium (sh

allow water) where they slow down. In what direction will the waves turn slightly, and why
Physics
2 answers:
MissTica3 years ago
8 0

Answer:

The waves will turn slightly to the <em><u>left .</u></em>

Explanation :

The waves will turn slightly to the left, because the left side of each wave front hits the boundary first and slows down, moving more slowly than the right side until the right side of the wave front reaches the boundary. THis causes the wave to veer slightly to the left.

  Basically the speed of water depends upon depth of the river or the ocean.

the formula is as follows :

            v =  √gxd

           v =  √d               (g is the gravitational acceleration)

As the water waves are more at the deeper end then the shallow end, so during its course to the shallower end, they are slightly deviated toward the normal., hence it will move slightly to the left.

koban [17]3 years ago
8 0

Answer:

The wave turn slightly to the bottom.

Explanation: Because part of the wave travel faster causing the wave to turn.

If the wave is moving from deep to shallow, as the depth approaches 1/2 a wavelength, things start to change - the wave will start to rise vertically and eventually brake. You can imagine the bottom of the wave hitting the sea bottom and slowing down, the frequency will go up, the velocity of the wave will go down.

As a wave moves into shallow water, its orbitals “feel the bottom,” causing it to slow down. This end is in shallower water, so it slows down towards the shore than the slower-moving end in.

Water waves will change direction at a boundary between deep and shallowwater. The waves slow down as they enter the shallow water which causes the wavelengths to shorten.

As waves travel into the denser medium, they slow down and wavelength decreases.Part of the wave travels faster for longer causing the wave to turn.The wave is slower but the wavelength is shorter meaning frequency remains the same.

You might be interested in
If the maximum tension in the simulation is 10.0 N, what is the linear mass density (m/L) of the string
vovikov84 [41]

Complete Question

The speed of a transverse wave on a string of length L and mass m under T is given by the formula

     v=\sqrt{\frac{T}{(m/l)}}

If the maximum tension in the simulation is 10.0 N, what is the linear mass density (m/L) of the string

Answer:

(m/l)=\frac{10}{V^2}

Explanation:

From the question we are told that

Speed of a transverse wave given by

v=\sqrt{\frac{T}{(m/l)}}

Maximum Tension is T=10.0N

Generally making (m/l) subject from the equation mathematically we have

v=\sqrt{\frac{T}{(m/l)}}

v^2=\frac{T}{(m/l)}

(m/l)=\frac{T}{V^2}

(m/l)=\frac{10}{V^2}

Therefore the Linear mass in terms of Velocity is given by

(m/l)=\frac{10}{V^2}

8 0
3 years ago
The maximum energy a bone can absorb without breaking is surprisingly small. For a healthy human of mass 60 kg60 kg, experimenta
netineya [11]

Answer:

<em>the maximum height a man can jump from and land rigidly upright on both feet without breaking his legs is 0.34 m</em>

<em></em>

Explanation:

Mass of a healthy man = 60 kg

energy the bone can take without breaking = 200 J

If a healthy man jumps from a height 'h', he falls with an energy equal to the potential energy due to his initial height above the ground.

initial potential energy of the healthy man = mgh

where m = mass of the man

g = acceleration due to gravity = 9.81 m/s^2

h = the height above ground

==> PE = 60 x 9.81 x h = 588.6h

If we assume that all energy is absorbed in the leg bones in a rigid landing, then we can safely say that this calculated PE for a healthy man is equal to the energy his bone can absorb in the jump without breaking.

equating, we have

200 = 588.6h

<em>the maximum height a man can jump from without breaking his legs = 200/588.6 = 0.34 m</em>

When people jump from a height, the sudden deceleration to zero can impact a big force on the leg bones, shattering them. If the time spent in decelerating to zero is increased, the overall force on the leg bones is reduced greatly.

<em>Bending the knees gradually on landing from a jump from a height, and then rolling increases the time spent decelerating, and reduces the impact force on the legs due to the landing</em>. If you observe carefully you will see that this is what professional stunts men and acrobats do when they jump from a height.

5 0
3 years ago
Please help with 9 &amp; 10
Tanzania [10]
Add all the sec. and all the meter's and then add the meter's and sec. together
4 0
3 years ago
If the mass of a materials is 44grams and the volume of the material is 11cm^3 what would the density of the material be
jok3333 [9.3K]
Density =mass/volume
density= (0.044kg/(11 x10^-6)
4000kg/m^3
8 0
3 years ago
The Celsius temperature scale is based on which of the following
Lapatulllka [165]
Freezing.................
6 0
3 years ago
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