Answer:
Explanation:
Let's use Ohm's law:
or
(1)
Where:
We know the value of the voltage V, so we need to find the value of R in order to find I. Fortunately there is a relation between the resistivity of a conductor and its electrical resistance given by:
(2)
Where:
Keep in mind that the electrical resistivity of the gold is a known constant which is 
and the cross sectional area of the conductor is calculated as:
Because we have a wire in this case, so we assume a cylindrical geometry.
Now replacing our data in (2)
Finally, we know R and V, so replacing these values in (1) we will be able to find the current:
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The word for Tepertaure is Celsius in the Metric System
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The potential difference across a and b is 15 v. determine the electrical charge on the 3 μf capacitor will be 45 * 
C
Capacitance, property of an electric conductor, or set of conductors, that is measured by the amount of separated electric charge that can be stored on it per unit change in electrical potential. Capacitance also implies an associated storage of electrical energy.
Charge (Q) stored in a capacitor is the product of its capacitance (C) and the voltage (V) applied to it. The capacitance of a capacitor should always be a constant, known value. So we can adjust voltage to increase or decrease the cap's charge. More voltage means more charge, less voltage... less charge.
charge = capacitance * voltage
Q = CV
= 3 * * 15 v
= 45 * C
To learn more about capacitance here
brainly.com/question/14746225
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