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grigory [225]
3 years ago
14

The student's lab manual says to mix some of his Na2CO3 solution with an aqueous solution of copper(II) sulfate (CuSO4)

Chemistry
1 answer:
lord [1]3 years ago
3 0

Explanation:

When the student mixed the solution sodium carbonate with solution of copper(II) sulfate ; Copper Hydroxocarbonate , sodium sulfate and carbon dioxide gas was obtained as a products.

The balanced chemical reaction

2Na_2CO_3+2CuSO_4\rightarrow Cu_2(OH)_2CO_3+2Na_2SO_4+CO_2

Where:

Cu_2(OH)_2CO_3 = Copper(II) Hydroxocarbonate

Na_2CO_3 = Sodium carbonate

CuSO_4 = Copper(II) sulfate

Na_2SO_4 = Sodium sulfate

CO_2 = Carbon-dioxide

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Lostsunrise [7]

Answer:

cover the taste with sugar add two times the amount your supposed to put in

Explanation:

3 0
3 years ago
A large balloon is initially filled to a volume of 25.0 L at 353 K and a pressure of 2575 mm Hg. What volume of gas will the bal
bija089 [108]

Answer:

45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.

Explanation:

Using Ideal gas equation for same mole of gas as

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

Given ,  

V₁ = 25.0 L

V₂ = ?

P₁ = 2575 mm Hg

Also, P (atm) = P (mm Hg) / 760

P₁ = 2575 / 760 atm = 3.39 atm

P₂ = 1.35 atm

T₁ = 353 K

T₂ = 253 K

Using above equation as:

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

\frac{{3.39}\times {25.0}}{353}=\frac{{1.35}\times {V_2}}{253}

\frac{1.35V_2}{253}=\frac{3.39\times \:25}{353}

Solving for V₂ , we get:

<u>V₂ = 45.0 L</u>

45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.

4 0
3 years ago
if the percent by volume is 2% and the volume of solution is 250 mL what is the volume of solute and solution
Liula [17]

Answer:

Solute = 5 mL; solution = 250 mL  

Explanation:

The formula for percent by volume is

\text{Percent by volume} = \dfrac{\text{Volume of solute}}{\text{Volume of solution}}\times 100 \, \%

If you have 250 mL of a solution that is 2 % v/v,

\begin{array}{rcl}2 \, \% & = & \dfrac{\text{Volume of solute}}{\text{250 mL}}\times 100 \, \%\\\\2 \times \text{ 250 mL} & = & \text{Volume of solute} \times 100\\\text{Volume of solute} & = & \dfrac{2 \times 250\text{ mL}}{100}\\\\ & = & \textbf{5 mL}\\\end{array}

If there is no change of volume on mixing,

Volume of solution = 250 mL

 -Volume of solute = <u>     </u><u>5</u><u>      </u>

 Volume of solvent = 245 mL

5 0
3 years ago
Potassium chlorate is a white, crystalline solid. It can be broken down into potassium chloride (a salt)
lions [1.4K]

Answer:

Notice that the number of atoms of

K

and

Cl

are the same on both sides, but the numbers of

O

atoms are not. There are 3

O

atoms on the the left side and 2 on the right. 3 and 2 are factors of 6, so add coefficients so that there are 6

O

atoms on both sides.

2KClO

3

(

s

)

+ heat

→

KCl(s)

+

3O

2

(

g

)

Now the

K

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Cl

atoms are not balanced. There are 2 of each on the left and 1 of each on the right. Add a coefficient of 2 in front of

KCl

.

2KClO

3

(

s

)

+ heat

→

2KCl(s)

+

3O

2

(

g

)

The equation is now balanced with 2

K

atoms,

7 0
3 years ago
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The 54.9-g sample of the compound X2O7 contains 33.6 g of oxygen atoms. What is the molar mass of element X?
vazorg [7]
Mass of X₂O₇ = 54,9g

2x + 33,6g = 54,9g
2x = 54,9g - 33,6g
2x = 21,3g  | :2
x = 10,65g/mol
7 0
3 years ago
Read 2 more answers
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