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SpyIntel [72]
3 years ago
9

Q1. In a 100m track event, the time taken by four runners is 10 sec., 10.2 sec., 10.4 sec and 10.6 sec. Find the ratio of their

speed.
Physics
1 answer:
Anna35 [415]3 years ago
8 0
Distance (s)=100m
time
T₁=10
T₂=10.2
T₃=10.4
T₄=10.6
by v=\frac{s}{t}
we get
V₁=\frac{100}{10}
V₁=10m/s

V₂=\frac{100}{10.2}
V₂=9.8m/s

V₃=\frac{100}{10.4}
V₃=9.61 m/s

V₄=\frac{100}{10.6}
V₄=9.43 m/s

V₁:V₂:V₃:V₄ = 10 : 9.8 : 9.61 : 9.43
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Hi there!

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Thus:

0 = vi - at

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9.8t = 16sin(33°)

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Svetlanka [38]

Answer:

\Delta V    = 1.8 \times 10^7 V

Explanation:

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Thus the alpha particle will

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