Given that the density of heptane is
![d_h=\frac{0.684g}{mL}](https://tex.z-dn.net/?f=d_h%3D%5Cfrac%7B0.684g%7D%7BmL%7D)
The mass of heptane is
![m_h=31\text{ g}](https://tex.z-dn.net/?f=m_h%3D31%5Ctext%7B%20g%7D)
The density of water is
![d_w=\frac{1g}{mL}](https://tex.z-dn.net/?f=d_w%3D%5Cfrac%7B1g%7D%7BmL%7D)
The mass of water is
![m_w=37\text{ g}](https://tex.z-dn.net/?f=m_w%3D37%5Ctext%7B%20g%7D)
The volume of heptane will be
![\begin{gathered} V_h=\frac{m_h}{d_h} \\ =\frac{31}{0.684} \\ =45.32\text{ mL} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20V_h%3D%5Cfrac%7Bm_h%7D%7Bd_h%7D%20%5C%5C%20%3D%5Cfrac%7B31%7D%7B0.684%7D%20%5C%5C%20%3D45.32%5Ctext%7B%20mL%7D%20%5Cend%7Bgathered%7D)
The volume of water will be
![\begin{gathered} V_w=\frac{m_w}{d_w} \\ =\frac{37}{1} \\ =37\text{ mL} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20V_w%3D%5Cfrac%7Bm_w%7D%7Bd_w%7D%20%5C%5C%20%3D%5Cfrac%7B37%7D%7B1%7D%20%5C%5C%20%3D37%5Ctext%7B%20mL%7D%20%5Cend%7Bgathered%7D)
Thus, the volume of heptane is 45.32 mL and the volume of water is 37 mL.
The total volume of liquid in the cylinder will be
![\begin{gathered} V=V_h+V_w \\ =45.32+37 \\ =82.32\text{ mL} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20V%3DV_h%2BV_w%20%5C%5C%20%3D45.32%2B37%20%5C%5C%20%3D82.32%5Ctext%7B%20mL%7D%20%5Cend%7Bgathered%7D)
The total volume of liquid in the cylinder will be 82.32 mL.
“Don't hand that holier than thou line to me” is what the asymptote
said to the removable discontinuity.
The distance between the
curve and the line where it approaches zero as they tend to infinity is the line in the asymptote
of a curve. This is unusual for modern authors but in some
sources the requirement that the curve may not cross the line infinitely often
is included.
The point that does not fit the rest of the graph or is
undefined is called a removable discontinuity. By filling in a single
point, the removable discontinuity can be made connected.
Answer:
![r = 2.84 \times 10^{-14} m](https://tex.z-dn.net/?f=r%20%3D%202.84%20%5Ctimes%2010%5E%7B-14%7D%20m)
Explanation:
As per energy conservation we know that the electrostatic potential energy of the charge system is equal to the initial kinetic energy of the alpha particle
So here we can write it as
![\frac{1}{2}mv^2 = \frac{k(2e)(ze)}{r}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dmv%5E2%20%3D%20%5Cfrac%7Bk%282e%29%28ze%29%7D%7Br%7D)
now we know that
![m = 1.67 \times 10^{-27} kg](https://tex.z-dn.net/?f=m%20%3D%201.67%20%5Ctimes%2010%5E%7B-27%7D%20kg)
![e = 1.6 \times 10^{-19} C](https://tex.z-dn.net/?f=e%20%3D%201.6%20%5Ctimes%2010%5E%7B-19%7D%20C)
z = 79
here kinetic energy of the incident alpha particle is given as
![KE = 6.4 \times 10^{-13} J](https://tex.z-dn.net/?f=KE%20%3D%206.4%20%5Ctimes%2010%5E%7B-13%7D%20J)
now we have
![6.4 \times 10^{-13} = \frac{(9\times 10^9)(1.6 \times 10^{-19})^2(79)}{r}](https://tex.z-dn.net/?f=6.4%20%5Ctimes%2010%5E%7B-13%7D%20%3D%20%5Cfrac%7B%289%5Ctimes%2010%5E9%29%281.6%20%5Ctimes%2010%5E%7B-19%7D%29%5E2%2879%29%7D%7Br%7D)
now we have
![r = 2.84 \times 10^{-14} m](https://tex.z-dn.net/?f=r%20%3D%202.84%20%5Ctimes%2010%5E%7B-14%7D%20m)
Answer:
38,437.5
Explanation:
Density(d)= 102.5g/ml
Volume (v)=375ml
Mass(m) = ?
D =m/v
102.5= m/375
102.5*375=m
38,437.5=m
therefore Mass = 38,437.5g/ml.
The gravitational forces between the Earth and Moon are greatest when the two bodies are closest together. That happens every 27.32 days, when the Moon is at the perigee of its orbit.
Even if this happened at the same time in every orbit, the date would change, because there are not 27.32 days in a month.
But it doesn't happen at the same time in every orbit ... the Moon's perigee precesses around its orbit, on account of the gravitational forces toward the Earth, the Sun, Venus, Mars, and the other planets.