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ZanzabumX [31]
4 years ago
10

A single drop of soda contains how many atoms?

Chemistry
1 answer:
Natalija [7]4 years ago
6 0
Since we are not given with any quantitative information, we have to rely on literature data. Suppose the soda drink referred to here is Coke. The density of a Coke at 20°C is 0.995 g/mL. A single drop of liquid is approximately 0.05 mL. From these two data, we can determine the mass of coke in a single drop.

Mass = 0.995 g/mL * 0.05 mL = 0.04975 g

We have to know the molar mass of Coke. Since majority of it is composed of sugar sucrose, let's take the value of the molar mass of sucrose: 342.2965 g/mol. Using the Avogadro's number (6.022×10²³ atoms/mol),

Number of atoms = 0.04975 g * (1 mol/342.2965 mol) * (6.022×10²³ atoms/mol) = 8.75×10¹⁹ atoms 
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I need help with 4, 5, 8, 9, and 6. Quickly I need it before class starts. Worth points!!!!!! HelP
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Answer:

4. 264.6J

5. 37.5J

6. 96J

7. 55Watts

8. 77.14m

9. 6s

10. 750Watts

Explanation:

4). Mechanical energy (potential energy) = mass (m) × acceleration due to gravity (g) × height (h)

m = 3kg, h = 9m, g = 9.8m/s²

P.E = 3 × 9 × 9.8

= 264.6J

5). Kinetic energy (K.E) = 1/2 × m × v²

Where;

m = mass (kg) = 3kg

v = velocity (m/s) = 5m/s

K.E = 1/2 × 3 × 5²

K.E = 1/2 × 3 × 25

K.E = 1/2 × 75

K.E = 37.5J

6). Work done (J) = Force (N) × distance (m)

Force = 12N, distance = 8m

Work done = 12 × 8

= 96J

7). Power = work done (J) ÷ time (s)

Work done = 550J, time = 10s

Power = 550/10

= 55Watts.

8). Work done = force (F) × distance (m)

Work done = 540J, force = 7N, distance = ?

540 = 7 × d

540 = 7d

d = 540/7

d = 77.14m

9). Power = work done (J) ÷ time (s)

Work done = 300J, time = ?, Power = 50Watts.

50 = 300/t

50t = 300

t = 300/50

t = 6seconds.

10). Power = work done (J) ÷ time (s)

This means that;

Power = force × distance / time

Force = 300N, distance = 5m, time = 2s

Power = 300 × 5 ÷ 2

Power = 1500 ÷ 2

Power = 750Watts

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3 years ago
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