How long will it be before 82.0 % of an isotope with a half life of 1250 y decays?
1 answer:
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Answer:
91.48N/m
Explanation:
In a spring-mass system undergoing a simple harmonic motion, the inverse of the frequency f, of oscillation is proportional to the square root of the mass m, and inversely proportional to the square root of the spring constant, k. This can be expressed mathematically as follows;
=
-----------(i)
From the question;
f = 3.26 Hz
m = 0.218kg
Substitute these values into equation (i) as follows;
=
[<em>Square both sides</em>]
()² = (
)²(
)
() =
²(
) [<em>Take </em>
<em> to be 3.142</em>]
() =
²(
)
() =
(
)
() = (
) [<em>Switch sides</em>]
() = (
) [<em>Re-arrange</em>]
() = (
) [<em>Cross-multiply</em>]
k = 8.608 x 10.6276
k = 91.48N/m
Therefore, the spring constant of the spring is 91.48N/m