830 mL. A 2.3 mol/L solution of CaCl2 has a volume of 830 mL
I am guessing that the concentration of your solution is 2.3 mol/L.
a) Moles of CaCl2
MM of CaCl2 = 110.98 g/mol
Moles of CaCl2 = 212 g CaCl2 x (1 mol CaCl2/110.98 g CaCl2)
= 1.910 mol CaCl2
b) Volume of solution
V = 1.910 mol CaCl2 x (1 L solution/2.3 mol CaCl2) = 0.83 L solution
= 830 mL solution
Independent variable would be salt since you can't change it in this experiment.
Answer:
The amount of solute added.
Explanation:
The amount of solute added is directly proportional to the number of ions.
The higher the amount added the higher the number of moles.
The number of moles is multiplied by the Avogadro's constant to get the number ions.
No of ions= No of moles × L
L is the Avogadro's number.
Answer: option A. to decrease the solubility of the organic product in water
Explanation: sodium chloride solution act as a drying agent to remove water from an organic compound that is in solution. The salt water works to pull the water from the organic layer to the water layer,therby decreasing
