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3 years ago

Describe how the ringing sound of a telephone travels through air

Physics

2 answers:

konstantin123 [22]3 years ago

6 0

Sound waves, duh. What do u expect?

snow_lady [41]3 years ago

4 0

It's sound waves. Ignore their rude comment

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URGENT. Please help.

exis [7]

1). c ... 2). d ... 3). a ... 4). d ... 5). c ... 6). a

7). b-mass ... c-m/s ... d-Newton's 1st ... e-Newton's 2nd

6 0

3 years ago

an athlete running 2.6m/ increases his velocity to 3.7m/s in 2.7s. what is the acceleration of the runner

iVinArrow [24]

Acceleration= velocity/time

1.1/2.7=0.41

The acceleration is .41 m/s^2

4 0

3 years ago

What force must the worker exert to get the box moving & what force must the worker exert to accelerate the box at 0.1 meter

photoshop1234 [79]

Since static friction is the minimum force required to just start the motion of a stationary object.

Here if we need to start an object from rest then we required F = 700 N

So for the first part of the above problem Force will be F = 700 N

Now if the box is already moving then we will have to use kinetic friction force between box and floor

now we can write the equation of net force as

$F - F_k = m*a$

here

$F_k = kinetic friction = 220 N$

$m = mass = 500 kg$

$a = acceleration = 0.1 m/s^2$

now we will have

$F - 220 = 500* 0.1$

$F = 220 + 50 = 270 N$

3 0

3 years ago

A block of plastic in the shape of a rectangular solid that has height 8.00 cm and area A for its top and bottom surfaces is flo

kifflom [539]

Answer:

0.35 kg

Explanation:

8 cm = 0.08 m

For the block to stay balance, the buoyancy force must be the same as gravity that pulls it down.

Let mass of the block be M, then the gravity would be Mg

Let water density be $\rho_w = 1000 kg/m^3$ , the buoyancy force would be the weight of water that is displaced by the submerged block.

For example, when there is no coin, block is $h_0 = 0.0312m$ submerged. The weight of water displaced must be

$W_0 = Ah_0\rho_wg = 0.0312A1000g = 31.2Ag$

Which is also the weight of block, of Mg

Therefore M = 31.2A. (1)

As coins are stacked on top of block, h increase, so as weight of water displaced and total weight of block and coins. Now let m be the total weight of coins. The gravity of block and weight must be (M+m)g. And the weight of water displaced is:

$W = Ah\rho g = (M + m)g$

$h = \frac{M}{A\rho} + \frac{m}{A\rho}$

Since the linear plot of h vs m has a slope of 0.089 m/kg, we can interpret it as

$\frac{1}{A\rho} = 0.089$

$A = \frac{1}{0.089\rho} = \frac{1}{89} = 0.011 m^2$

So from the eq. (1) we can solve for M = 31.2A = 0.35 kg

8 0

3 years ago

The pressure exerted by 15m of liquid is 1500pa.The acceleration due to gravity g=10m/s^2.Calculate the density liquid.

Natali [406]

Answer:

1500 divided by 150(15m x 10m/s^2) = 10

8 0

3 years ago