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Trava [24]
3 years ago
11

Which of the following assumptions appears reasonable for the isothermal process? H20 (liq, 1 bar) → H2O (liq, 1300 bar), T = 20

°C. A. AU = 0, AH 0 B. AU = 0, AH 0 C. AU #0, AH = 0 D. None of the above Hinn nf diethyl ether using the Chen's rule is
Chemistry
1 answer:
Vitek1552 [10]3 years ago
3 0

Answer : The assumptions appears reasonable for the isothermal process is, \Delta U=0 and \Delta H=0

Explanation :

First law of thermodynamic : It states that the energy can not be created or destroyed, it can only change or transfer from one state to another state.

As per first law of thermodynamic,

\Delta U=q+w

The expression for internal energy is:

\Delta U=nC_vdt

The expression for enthalpy is:

\Delta H=nC_pdt

where,

\Delta U = internal energy

q = heat

w = work done

n = number of moles

C_v = specific heat capacity at constant volume

C_p = specific heat capacity at constant pressure

dt = change in temperature

As we know that, the term internal energy and enthalpy is the depend on the temperature and the process is isothermal that means at constant temperature.

T = constant

\dt = 0

So, at constant temperature the internal energy and enthalpy is equal to zero. That means,

\Delta U=0 and \Delta H=0

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Answer:

470 °C  

Explanation:

This looks like a case where we can use Charles’ Law:  

\dfrac{V_{1}}{T_{1}} =\dfrac{V_{2}}{T_{2}}

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(b) Calculate the new temperature

\begin{array}{rcl}\dfrac{V_{1}}{T_{1}}& =&\dfrac{V_{2}}{T_{2}}\\\\ \dfrac{\text{20 L}}{\text{373.15 K}} &=&\dfrac{\text{40 L}}{T_{2}}\\\\{\text{15 000 K}} & = & 20T_{2}\\T_{2} & = &\dfrac{\text{15 000 K}}{20 }\\\\T_{2} & = & \textbf{750 K}\\\end{array}

Note: The answer can have only two significant figures because that is all you gave for the volumes.

(c) Convert the temperature to Celsius

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3 years ago
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