which of the following are vector quantities? check all that apply. a. time b. displacement c. force d. mass

In an elastic head-on collision, a 0.60 kg cart moving at 5.0 m/s [W] collides with a 0.80 kg cart moving at 2.0 m/s [E]. The co

labwork [276]

Answer:

The answer is given below

Explanation:

u is the initial velocity, v is the final velocity. Given that:

$m_1=0.6kg,u_1=-5m/s(moving \ west),m_2=0.8kg,u_2=2m/s,k=1200N/m$

a)

The final velocity of cart 1 after collision is given as:

$v_1=(\frac{m_1-m_2}{m_1+m_2})u_1+\frac{2m_2}{m_1+m_2}u_2\\ Substituting:\\v_1=\frac{0.6-0.8}{0.6+0.8} (-5)+\frac{2*0.8}{0.6+0.8}(2)= 5/7+16/7=3\ m/s$

The final velocity of cart 2 after collision is given as:

$v_2=(\frac{m_2-m_1}{m_1+m_2})u_2+\frac{2m_1}{m_1+m_2}u_1\\ Substituting:\\v_1=\frac{0.8-0.6}{0.6+0.8} (2)+\frac{2*0.6}{0.6+0.8}(-5)= 2/7-30/7=-4\ m/s$

b) Using the law of conservation of energy:

$\frac{1}{2}m_1u_1+ \frac{1}{2}m_2u_2=\frac{1}{2}m_1v_1+\frac{1}{2}m_2v_2+\frac{1}{2}kx^2\\x=\sqrt{\frac{m_1u_1+m_2u_2-m_1v_1-m_2v_2}{k}}\\ Substituting\ gives:\\x=\sqrt{\frac{0.6*(-5)^2+0.8*2^2-(0.6*3^2)-(0.8*(-4)^2)}{1200}}=\sqrt{0}=0\ cm$

7 0

3 years ago

How much heat is absorbed by a 450g gold block as energy from the sun causes its temperature to change from 27°C to 32°C? (Speci

kotegsom [21]

Answer:

Q = 1057.5 [cal]

Explanation:

In order to solve this problem, we must use the following equation of thermal energy.

$Q=m*C_{p}*(T_{final}-T_{initial})$

where:

Q = heat energy [cal]

Cp = specific heat = 0.47 [cal/g*°C]

T_final = final temperature = 32 [°C]

T_initial = initial temperature = 27 [°C]

m = mass of the substance = 450 [g]

Now replacing:

$Q=450*0.47*(32-27)\\Q=1057.5[cal]$

5 0

2 years ago

Object A has a mass m and a speed v, object B has a mass m/2 and a speed 4v, and object C has a mass 3m and a speed v/3. Rank th

borishaifa [10]

We need to rank the objects according to the magnitude of their momentum.

We know momentum , $P = m\times v$ { here m is mass and v is velocity }

Momentum of object A , $P_A = m v.$

Momentum of object B , $P_B= \dfrac{m}{2}\times4v=2\ mv.$

Momentum of object C , $P_C= 3m\times\dfrac{v}{3}=mv.$

Now, we can rank them in order of their magnitude of momentum .

$P_B>P_A=P_C$ .

Hence, this is the required solution.

Learn More :

Momentum

brainly.com/question/7957458

5 0

3 years ago

You push a table 8 meters for 16 minuutes and do 6720 j of work how much power do ypu use

Yuri [45]

P=W/t

P=Power
W=Work
t=Time

Convert 16 minutes in seconds:
16 mins = 960 secs

P=6720/960=7.23 W [Watt]

3 0

3 years ago

When the liquid line is restricted, the supply of refrigerant to the metering device is reduced. What is the effect on suction p

Nimfa-mama [501]

Answer:

The suction pressure decreases and the superheat increases when the liquid line is restricted and the supply of refrigerant to the metering device is reduced.

Explanation:

1. The five components of refrigeration are:

Fluid refrigerant
Compressor
Condenser coil
Evaporator coil
Expansion device.

The compressor limits the vapor released by the refrigerant. This

causes a rise in pressure (in refrigerant), which then pushes the

vapor into the coils on the outside of the refrigerator.

2. Now when the cooler air meets the warm gas present in the coils, it

gets converted into liquid form.

3. Thus, when the liquid form is at high pressure, the refrigerant then

cools down as it flows through the coils placed in the fridge ( in both

freezing and normal sections).

4. The refrigerant also absorbs the warm air present in the fridge, which

causes it to evaporate and flow back through the compressor and the

cycle repeats in the same form.

Thus, when the liquid line is restricted and the supply of refrigerant to the metering device is reduced it causes a decrease in suction pressure and an increase in superheat.

Learn more about refrigeration here:

<u>brainly.com/question/9046279</u>

#SPJ4

8 0

1 year ago