Question

An object has 60 j of potential energy and 40 j of kinetic energy. then 10 j of the potential energy is converted into kinetic energy. how much work was done on the object?

Answer 1

It will be 50 J because if he worked on 40 J already then he converted 10 j to ke Eric energy making it 50:50. So he work on 50% already and needs to complete the rest of the 50%.

Answer 2

Answer:

work done on the object will be 10 J

Explanation:

As we know by work energy theorem that work done by all the forces is equal to change in kinetic energy

It is given as

$K_f - K_i = W$

here we know that

$K_i = 40 J$

now its 10 J of potential energy is converted into kinetic energy

Which means the kinetic energy finally becomes

$K_f = 40 + 10 = 50 J$

now by above equation we know that

$W = K_f - K_i$

$W = 50 - 40 = 10 J$

so work done on the object will be 10 J