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3 years ago

Which orbital notation represents a noble gas in the ground state

Chemistry

1 answer:

MA_775_DIABLO [31]3 years ago

6 0

In order to represent a noble gas the Orbital notation should be equal to 2, 8 or 18 for eg. 1s²

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What is the total number of calories of heat energy absorbed when 10 grams of water is vaporized at its normal boiling point

Darya [45]

Answer: The amount of energy absorbed by water is 5390 Calories

Explanation:

To calculate the amount of heat absorbed at normal boiling point, we use the equation:

$q=m\times L_{vap}$

where,

q = amount of heat absorbed = ?

m = mass of water = 10 grams

$L_{vap}$ = latent heat of vaporization = 539 Cal/g

Putting values in above equation, we get:

$q=10g\times 539Cal/g=5390Cal$

Hence, the amount of energy absorbed by water is 5390 Calories

6 0

3 years ago

How many molecules of H2O are equivalent to 98.2 g of H2O

GREYUIT [131]

Answer:

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Explanation:

3 0

3 years ago

Exercise A mixture of 250 mL of methane, CH4, at 35 °C and 0.55 atm and 750 mL of propane, C3Hg, at 35° C and 1.5 atm, were intr

dalvyx [7]

Explanation:

The given data is as follows.

$V_{1}$ = 250 mL, $V_{2}$ = 750 mL

$T_{1}$ = $35^{o}C$ = 35 + 273 K = 308 K

$T_{2}$ = 35 + 273 K = 308 K

$P_{1}$ = 0.55 atm, $P_{2}$ = 1.5 atm

P = ? , V = 10.0 L

Since, temperature is constant.

So, $P_{1}V_{1} + P_{2}V_{2}$ = PV

Now, putting the given values into the above formula as follows.

$P_{1}V_{1} + P_{2}V_{2}$ = PV

$0.55 atm \times 250 mL + 1.5 atm \times 1.5 atm$ = $P \times 10.0 L$

P = 0.126 atm

As, 1 atm = 760 torr. So, $0.126 atm \times \frac{760 torr}{1 atm}$ = 95.76 torr.

Thus, we can conclude that the final pressure, in torr, of the mixture is 95.76 torr.

8 0

3 years ago

How many places are there electrons in the innermost shell of an atom

Sergio [31]

There are two places for electrons in the inner most shell

5 0

4 years ago

Explain the reaction of metals with water.

telo118 [61]

Answer:

it rusts

Explanation:

4 0

4 years ago