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harkovskaia [24]
3 years ago
13

How many atoms of a chlorine element would be needed to react with one atomic of helium

Chemistry
1 answer:
lubasha [3.4K]3 years ago
6 0

Question: How many atoms of a chlorine element would be needed to react with one atom of helium?

Answer: <u>So... for the element of CHLORINE, you already know that the atomic number tells you the number of electrons. That means there are 17 electrons in a chlorine atom. Looking at the picture, you can see there are two electrons in shell one, eight in shell two, and seven in shell three.</u>

<em>Hope this helps!.</em>

<em>~~~~~~~~~~~~~~~~~~</em>

<em>~A.W~ZoomZoom44</em>

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How many milligrams of magnesium reacts with excess HCl to produce 31.2 mL of hydrogen gas at 754 Torr and 25.0℃.
Ivanshal [37]

Answer:

There will react 30.9 milligrams of magnesium

Explanation:

Step 1: Data given

Volume of hydrogen = 31.2 mL

Pressure = 754 torr = 754/760 = 0.992 atm

Temperature = 25.0 °C = 298 Kelvin

Step 2: The balanced equation

Mg + 2HCl → MgCl2 + H2

Step 3: Calculate moles of H2

p*V = n*R*T

⇒ with p = the pressure of H2 = 0.992 atm

⇒with V = the volume of H2 = 31.2 mL = 0.0312 L

⇒ with n = the moles of H2 = TO BE DETERMINED

⇒ with R = the gas constant = 0.08206 L*atm/K*mol

⇒ with T= the temperature = 25.0 °C = 298 Kelvin

n = (p*V)/(R*T)

n = (0.992*0.0312)/(0.08206*298)

n = 0.00127 moles

Step 4: Calculate moles of Mg

For 1 mol of Mg we need 2 moles of HCl to produce 1 mol of MgCl2 and 1 mol of H2

For 0.00127 moles of H2 we need 0.00127 moles of Mg

Step 5: Calculate mass of Mg

Mass of Mg = moles of Mg * molar mass of Mg

Mass of Mg = 0.00127 moles * 24.3 g/mol

Mass of Mg = 0.0309 grams = 30.9 mg of Mg

There will react 30.9 milligrams of magnesium

3 0
2 years ago
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