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harkovskaia [24]
4 years ago
13

How many atoms of a chlorine element would be needed to react with one atomic of helium

Chemistry
1 answer:
lubasha [3.4K]4 years ago
6 0

Question: How many atoms of a chlorine element would be needed to react with one atom of helium?

Answer: <u>So... for the element of CHLORINE, you already know that the atomic number tells you the number of electrons. That means there are 17 electrons in a chlorine atom. Looking at the picture, you can see there are two electrons in shell one, eight in shell two, and seven in shell three.</u>

<em>Hope this helps!.</em>

<em>~~~~~~~~~~~~~~~~~~</em>

<em>~A.W~ZoomZoom44</em>

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7 0
3 years ago
When Mendeleev started his work on organizing the elements, about how many had
Talja [164]

Answer:

About 60.

Explanation:

Mendeleev knew of 63 elements. He wrote their properties on cards and arranged them in order of atomic mass.

That's how he discovered that the properties of elements are periodic functions of their atomic masses.

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3 years ago
How many moles do you have in 37.3 g of Co(CrO4)3​
shutvik [7]

Answer:

0.0917 mol Co(CrO₄)₃

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

37.3 g Co(CrO₄)₃

<u>Step 2: Identify Conversions</u>

Molar Mass of Co - 58.93 g/mol

Molar Mass of Cr - 52.00 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Co(CrO₄)₃ - 58.93 + 3(52.00) + 12(16.00) = 406.93 g/mol

<u>Step 3: Convert</u>

<u />37.3 \ g \ Co(CrO_4)_3(\frac{1 \ mol \ Co(CrO_4)_3}{406.93 \ g \ Co(CrO_4)_3} ) = 0.091662 mol Co(CrO₄)₃

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

0.091662 mol Co(CrO₄)₃ ≈ 0.0917 mol Co(CrO₄)₃

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3 years ago
Plant cells have a large central vacuole, which animal cells lack. What function does this organelle perform?
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5 0
3 years ago
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Answer:

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(Correct me if I am wrong)

4 0
3 years ago
Read 2 more answers
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