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Snezhnost [94]
3 years ago
7

Describe the solubility of water compared to ethanol?

Chemistry
1 answer:
Neko [114]3 years ago
4 0
As you know ethanol is a an alcohol and alcohol is a hydrocarbon. Alcohol is made up of a carbon chain which Is always non polar and a OH group which is polar. According to the solubility rule like substances dissolves like substance. Using ethanol chemical formula. Ethanol has a 2 carbon chain and a OH group. water is polar so it will be attracted to the OH group. Carbon chain on the other hand is nonpolar so it will be repelled from the water.


Therefore the Solubility of alcohols is determined by the stronger of the two forces. The strength of the attraction of the OH group, and the amount of water they dissolve in.
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Answer:

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Explanation:

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cricket20 [7]

The mass percent of hydrogen in CH₄O is 12.5%.

<h3>What is the mass percent?</h3>

Mass percent is the mass of the element divided by the mass of the compound or solute.

  • Step 1: Calculate the mass of the compound.

mCH₄O = 1 mC + 4 mH + 1 mO = 1 (12.01 amu) + 4 (1.00 amu) + 1 (16.00 amu) = 32.01 amu

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  • Step 3: Calculate the mass percent of hydrogen in the compound.

%H = (mH in mCH₄O / mCH₄O) × 100%

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Learn more about mass percent here:brainly.com/question/4336659

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How many half-lives will pass by the time 1.56% of I-131 is present? B. Approximately how many days does that equal? *
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Answer: Hmmmmm that's crazy....

There are a couple of equations one could use for this type of problem, but I find the following to be the easiest to use and to understand.

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n = number of half lives that have elapsed

In this problem, we need to find n and are given the FR, which is 1.56% or 0.0156 (as a fraction).

0.0156 = 0.5n

log 0.0156 = n log 0.5

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Explanation:

Just wanted to help. Hopefully it's correct wouldn't want to waster your time ;)

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