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zepelin [54]
3 years ago
14

When performing physical exercise, the heart rate, by what percentage can it be increased?

Chemistry
2 answers:
Dafna11 [192]3 years ago
4 0

Answer:

10

Explanation:

I did that already. You got beo

Lina20 [59]3 years ago
3 0

Answer: 50% to 85% of the person’s maximum heart rate.

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Please look at photo provided and help answer. Due soon please help!!!
saul85 [17]

Answer:

a. 6 mol of oxygen

b. 10 mol of iron(III)oxide

Explanation:

Use mole concept.

3 0
2 years ago
21. an atom has 216 protons, how many electrons does it have?
yanalaym [24]

Answer:

21: 47 22: 14

Explanation:

4 0
2 years ago
One mole of an ideal gas<br><br> occupies a volume of 22.4<br><br> liters at
-Dominant- [34]

Answer : One mole of an ideal gas  occupies a volume of 22.4  liters at STP.

Explanation :

As we know that 1 mole of substance occupies 22.4 liter volume of gas at STP conditions.

STP stands for standard temperature and pressure condition.

At STP, pressure is 1 atm and temperature is 273 K.

By using STP conditions, we get the volume of 22.47 liter.

Hnece, the one mole of an ideal gas  occupies a volume of 22.4  liters at STP.

3 0
3 years ago
Sea water is an electrolyte.<br> True<br> False
antoniya [11.8K]
If you are talking about just pure regular water, the answer is false. BUT, some salts dissolved IN WATER, can act as electrolytes. But regular water, no.
8 0
3 years ago
Read 2 more answers
A sample of gas has a volume of 100.0 L at 135°C. Assuming the pressure remains constant, what is the volume of the gas if its t
lina2011 [118]

Answer: 84.56L

Explanation:

Initial volume of gas V1 = 100L

Initial temperature T1 = 135°C

Convert temperature in Celsius to Kelvin

( 135°C + 273 = 408K)

Final temperature T2 = 72°C

( 72°C + 273= 345K)

Final volume V2 = ?

According to Charle's law, the volume of a fixed mass of a gas is directly proportional to the temperature.

Mathematically, Charles' Law is expressed as: V1/T1 = V2/T2

100L/408K = V2/345K

To get the value of V2, cross multiply

100L x 345K = V2 x 408K

34500 = V2 x 408K

V2.= 34500/408

V2 = 84.56L

Thus, the volume of the gas becomes 84.56 liters

8 0
3 years ago
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