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Mariana [72]
3 years ago
13

Why is the recruitment and selection of staff the concern of all managers in an organization? ​

Physics
1 answer:
leva [86]3 years ago
7 0

Answer:

Explanation:

It is a concern to managers in an organization because it is important for the organization to get the number and quality of staffs needed to attain the goals and objectives of the organization.

Selection and recruitment is also important in order to ensure the continuity of the company , it will also fulfills the organisations job requirements and also this provide a pool of employees in which the management will have to choose the right or best candidates for the job position.

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It comes from the sun, and then it is converted to energy/electricity (by solar panels)
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An igneous intrusion whose boundaries lie parallel to the layering in the surrounding country rock is considered to be:
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<span>...a concordant intrusion. In geology, "concordant" means the same as "sill" -- or, an intrusion that has gotten in between older layers of rock (or even beds of volcanic lava). An intrusion with boundaries parallel to layering in surrounding rocks suggests this, meaning it is considered to be a concordant intrusion.</span>
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PSYCHOLOGY. Which of the following statements does not describe a limitation of statistics?
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Answer:

<em>A. Statistics addresses gaps in knowledge.</em>

Explanation:

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To make sure you understand how to use the equation, suppose that there are 1000 habitable planets in our galaxy, that 1 in 10 h
krok68 [10]

Answer:

5

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Fraction of planet with life and civilization (before) = 1/4

Fraction of planet with life and civilization (now) =1/5

Therefore multiplying we have:

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3 years ago
A horizontal force of magnitude 30.2 N pushes a block of mass 3.50 kg across a floor where the coefficient of kinetic friction i
marshall27 [118]

Answer:

A) 89.39 J

B) 30.39J

C) 23.8 J

Explanation:

We are given;

F = 30.2N

m = 3.5 kg

μ_k = 0.646

d = 2.96m

ΔEth (Block) = 35.2J

A) Work done by the applied force on the block-floor system is given as;

W = F•d

Thus, W = 30.2 x 2.96 = 89.39 J

B) Total thermal energy dissipated by the whole system which includes the floor and the block is given as;

ΔEth = μ_k•mgd

Thus, ΔEth = 0.646 x 3.5 x 9.8 x 2.96 = 65.59J

Now, we are given the thermal energy of the block which is ΔEth (Block) = 35.2J.

Thus,

ΔEth = ΔEth (Block) + ΔEth (floor)

Thus,

ΔEth (floor) = ΔEth - ΔEth (Block)

ΔEth (floor) = 65.59J - 35.2J = 30.39J

C) The total work done is considered as the sum of the thermal energy dissipated as heat and the kinetic energy of the block. Thus;

W = K + ΔEth

Therefore;

K = W - ΔEth

K = 89.39 - 65.59 = 23.8J

3 0
3 years ago
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