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Mariana [72]
3 years ago
13

Why is the recruitment and selection of staff the concern of all managers in an organization? ​

Physics
1 answer:
leva [86]3 years ago
7 0

Answer:

Explanation:

It is a concern to managers in an organization because it is important for the organization to get the number and quality of staffs needed to attain the goals and objectives of the organization.

Selection and recruitment is also important in order to ensure the continuity of the company , it will also fulfills the organisations job requirements and also this provide a pool of employees in which the management will have to choose the right or best candidates for the job position.

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Two violinists are trying to tune their instruments in an orchestra. One is producing the desired frequency of 440.0 hz. The oth
Katyanochek1 [597]

Answer:

Percentage change in tension is 3.8%

Explanation:

We have given initially frequency f_1 = 440 Hz

Let tension in the string at this frequency is T_1

Now second frequency is f_2=448.4Hz

Frequency in string is given by

f=\frac{1}{2L}\sqrt{\frac{T}{\mu }}

From the relation we can say that

\frac{f_1}{f_2}=\sqrt{\frac{T_1}{T_2}}

\frac{440}{448.4}=\sqrt{\frac{T_1}{T_2}}

{\frac{T_2}{T_1}}=1.038

Percentage change in tension is equal to

=\frac{T_2-T_1}{T_1}=\frac{T_2}{T_1}-1=(1.038-1)\times 100=3.8 %

So percentage change in tension is 3.8%

4 0
3 years ago
The diver is on a board3.00m above the water. She jumps straight up at 3.25m/s. How many seconds later does she hit the water.
tigry1 [53]
Speed =distance/time
3.25=3.00/time
3.25xt=3.00
t=3/3.25
s=0.9s
5 0
3 years ago
What is the net torque on the square plate, with sides 0.2 m, from each of the three forces? F1=18 N, F2=26 N, and F3=14 N. Use
marshall27 [118]

Answer:

The net torque on the square plate is 2.72 N-m.

Explanation:

Given that,

Side = 0.2 m

Force F_{1}=18\ N

Force F_{2}=26\ N

Force F_{3}=14\ N

We need to calculate the torque due to force F₁

Using formula of torque

\tau_{1}=-F_{1}d_{1}

\tau_{1}=-F_{1}\times\dfrac{a}{2}

Put the value into the formula

\tau_{1}=-18\times\dfrac{0.2}{2}

\tau_{1}=-1.8\ N-m

We need to calculate the torque due to force F₂

Using formula of torque

\tau_{2}=F_{2}d_{2}

\tau_{2}=F_{2}\times\dfrac{a}{2}

Put the value into the formula

\tau_{2}=26\times\dfrac{0.2}{2}

\tau_{2}=2.6\ N-m

We need to calculate the torque due to force F₃

Using formula of torque

\tau_{3}=F_{3}d_{3}

\tau_{3}=(F_{3}\sin45+F_{3}\cos45)\times\dfrac{a}{2}

Put the value into the formula

\tau_{3}=0.1(14\sin45+14\cos45)

\tau_{3}=1.92\ N-m

We need to calculate the net torque on the square plate

\tau=\tau_{1}+\tau_{2}+\tau_{3}

\tau=-1.8+2.6+1.92

\tau=2.72\ N-m

Hence, The net torque on the square plate is 2.72 N-m.

3 0
3 years ago
**URGENT, I WILL PAY 30 POINTS, PLEASE HELP**
melamori03 [73]

All three windows are the same size.

A has 10 complete waves visible through the window. B has 3, and C has 4.

So A must have the smallest wavelengths.

4 0
3 years ago
Read 2 more answers
If two items are equal in size, the denser one will
Talja [164]
Be heavier

density=mass÷volume

if two items have the same size they have the same volume so the heavier one will be the denser one
6 0
3 years ago
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