Question

A technical machinist is asked to build a cubical steel tank that will hold 195 L of water. Calculate in meters the smallest possible inside length of the tank. Round your answer to the nearest 0.001 m.

Answer 1

Answer:

The smallest possible inside length of the tank is $0.579$ m.

Explanation:

As we know that

$1 m^3 = 1000 L$

Thus, volume of $195$ liter tank is also equal to $0.195$ cubic meter

The volume of a cube is equal to $x^3$, where, x is the length of the side of the cube

With the give condition,

$x^ 3 = 0.195$

Solving the above equation, we get -

$x = (0.195)^{\frac{1}{3})}\\x = 0.579$

The smallest possible inside length of the tank is $0.579$ m.