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Degger [83]
3 years ago
12

The Doppler shift may be helpful for someone trying to _______. overcome a visual illusion block out irrelevant noises locate so

unds see an object in very dim light
Physics
1 answer:
mestny [16]3 years ago
8 0

Answer:

The Doppler shift may be helpful to determine the relative speed of an object by bouncing a wave (usually a radar wave) off the object and measuring the shift in the frequency of the wave.

Explanation:

Doppler shift helps to overcome a visual illusion block out irrelevant noises, locate sounds and see an object in very dim light by determining the relative speed of an object by bouncing a wave

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Explain what is meant by the term mechanical advantage.
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Mechanical advantage is a measure of the force amplification achieved by using a tool, mechanical device or machine system.

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Which pair of quantities represents scalar quantities
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physical quantity that only has magnitude and no other characteristics.

Explanation:

so no velocity only magnitude

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An astronaut is in an all-metal chamber outside the space station when a solar storm results in the deposit of a large positive
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<em>c. The astronaut does not need to worry: the charge will remain on the outside surface.</em>

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How many electrons are available for bonding in oxygen
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4 years ago
A cart starts at x = +6.0 m and travels towards the origin with a constant speed of 2.0 m/s. What is it the exact cart position
Ira Lisetskai [31]

Answer:

At the origin (x' = 0 m)

Explanation:

Note: From the question, when the cart travels towards the origin, the magnitude of its exact position reduces with time.

The formula of speed is given as

S = d/t................. Equation 1

Where S = speed of the cart, d = distance covered by the cart over a certain time. t = time taken to cover the distance.

make d the subject of the equation,

d = St ................. Equation 2

Given: S = 2.0 m/s, t = 3.0 s

Substitute into equation 2

d = 2(3)

d = 6 m.

From the above, the cart covered a distance of 6 m in 3 s.

The exact position of the cart = Initial position-distance covered

x' = x-d............ Equation 3

Where x' = exact position of the cart 3 s later, x = initial position of the cart, d = distance covered by the cart in 3.0 s.

Given: x = +6.0 m, d = 6 m.

Substitute into equation 3

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x' = 0 m.

Hence the cart will be at 0 m (origin) 3 s later

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