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xxMikexx [17]
3 years ago
7

Which type of mountain is created when rock layers are pushed up by forces inside the Earth?

Physics
1 answer:
antoniya [11.8K]3 years ago
6 0
Upwarped mountain is created when rock layers are pushed up by forces inside the Earth.
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What is the identity of a sample that has a volume of 92.5 cm3 and a mass of 249.8 g?
denpristay [2]
Here, We know, Density = Mass / Volume
Here, mass = 249.8 g
volume = 92.5 cm³

Substitute their values, 
d = 249.8 / 92.5
d = 2.7 g/cm³

In short, Your Answer would be "Aluminum" 

Hope this helps!
3 0
3 years ago
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Newton’s law of gravitation says that gravity is a mutually attractive force. Explain the following observation: A small object
Airida [17]

Answer: See below

Explanation:

The Earth attracts the falling object with the same intensity of gravity as the object attracts the Earth, according to Newton's law of gravitation. The displacement of the two bodies, however, is inversely proportional to their respective masses.

Example: The Earth attracts a ball that falls 3 metres from the ground, even though the ball's mass is insignificant in comparison to the Earth's. Similarly, the ball draws the Earth with the same power, but the Earth's mass is enormously more than the ball's. As a result, the Earth collides with a billionth of a millimetre ball (or even less). Restart the Earth's descent on the ball you'll never see again.

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4 0
2 years ago
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A person who weighs 614 N is riding a 85-N mountain bike. Suppose the entire weight of the rider plus bike is supported equally
san4es73 [151]

Answer:

3.88 × 10^-4 m

Explanation:

Given that a  person who weighs 614 N is riding a 85-N mountain bike. Suppose the entire weight of the rider plus bike is supported equally by the two tires. If the gauge pressure in each tire is 9.00 x 10^5 Pa. What is the area of contact between each tire and the ground?

The total weight = 614 + 85

The total weight = 699N

Let the total area of contact = A

Pressure = Force / A

Substitute all the parameters into the formula

900000 = 699 /A

A = 699 / 900000

A = 7.77 × 10^-4 m

The area of contact between each tire and the ground will be = A/2

That is, 7.77 / 2 = 3.88 × 10^-4 m

Therefore, the area of contact between each tire and the ground is 3.88 × 10^-4 m approximately.

5 0
3 years ago
Why do people think its ok to hit on someone thats taken?
algol13
Well somethin called people who are jelous or want popularity.
7 0
2 years ago
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Deena made a chart to summarize features of a velocity vs. time graph for objects with constant acceleration and objects with co
Irina-Kira [14]
The error is:
"<span>Find acceleration by finding the area of the rectangle above the line"

The acceleration of any body is the rate of change of velocity of that body. If the motion of the object being considered is plotted on a graph, with the velocity on the y-axis and the time on the x-axis, this ratio will be equivalent to the slope of the graph, not the area above the line.</span>
5 0
3 years ago
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