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4 years ago

12

When you place a saturated sodium bicarbonate solution in with the mixture in the separatory funnel, a gas should be evolved. Is

this evidence your desired product is present?

2 answers:

netineya [11]4 years ago

7 0

Answer:

Yes

Explanation:

It causes excess bromine to be given off as a gas. -It is used to absorb excess heat generated by the exothermic reaction.

Oliga [24]4 years ago

5 0

Answer

The desired product should contain acidic group like -COOH group.

Explanation:

Saturated sodium bicarbonate solution will react with a acid compound which contain in reaction mixture and produce CO2 gas.

We have the reaction has;

NaHCO3 (aq) + R-COOH (aq) ..............> R-COONa (aq) + H2O (l) + CO2 (g)

Therefore.

The desired product will contain acidic group like -COOH (carboxylic acid group).

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Given the following solutions: Solution A: pH of 10 Solution B: pH of 7 Solution C: pH of 5 Which list has the solutions placed

Butoxors [25]

Answer:

Explanation:

H+ is a representation of the number if hydrogen ions also known as acidity of a substance, it is well known that pH <7 represents acidity and acidity increases from 6 to 0. 7 i known as neutral, while 8-14 represents alkalinity/base. pH scale ranges from 0-14. pH 10, 7, 5 is the order of increasing H+.

3 0

4 years ago

Which of the following has the shortest bond lenght Options A). H2 B).N2 C).O2 D).F2

hammer [34]

Answer:

B. N2

Explanation:

The triple bonds pull the atoms closer together, and since N2 is the only molecule with the triple bond, it is the shortest bond length.

6 0

4 years ago

Identify the examples of diffusion in the list below

Sergeu [11.5K]

Answer:

movement of particles of object from one place to another

e.g

spreading of perfume in air

spreading of ink in water

Explanation:

3 0

4 years ago

Read 2 more answers

Elements that do not have full outer electron shells will donate, share, or take from other atoms. Choose the items that have th

Gnesinka [82]

Answer:

Ok...

Answer: YTH/JYG

Explanation:

AI+ZN+H=YTH

7 0

4 years ago

We want to calculate the concentrations of all species in a 0.58 M Na 2 SO 3 (sodium sulfite) solution. The ionization constants

NeX [460]

Explanation:

Reaction equation is as follows.

$Na_{2}SO_{3}(s) \rightarrow 2Na^{+}(aq) + SO^{2-}_{3}(aq)$

Here, 1 mole of $Na_{2}SO_{3}$ produces 2 moles of cations.

$[Na^{+}] = 2[Na_{2}SO_{3}] = 2 \times 0.58$

= 1.16 M

$[SO^{2-}_{3}] = [Na_{2}SO_{3}]$ = 0.58 M

The sulphite anion will act as a base and react with $H_{2}O$ to form $HSO^{-}_{3}$ and $OH^{-}$ .

As, $K_{b} = \frac{K_{w}}{K_{a_{2}}}$

= $\frac{10^{-14}}{6.3 \times 10^{-8}}$

= $1.59 \times 10^{-7}$

According to the ICE table for the given reaction,

$SO^{2-}_{3} + H_{2}O \rightleftharpoons HSO^{-}_{3} + OH^{-}$

Initial: 0.58 0 0

Change: -x +x +x

Equilibrium: 0.58 - x x x

So,

$K_{b} = \frac{[HSO^{-}_{3}][OH^{-}]}{[SO^{2-}_{3}]}$

$1.59 \times 10^{-7} = \frac{x^{2}}{0.58 - x}$

$x^{2} = 1.59 \times 10^{-7} \times (0.58 - x)$

x = 0.0003 M

So, x = $[HSO^{-}_{3}] = [OH^{-}]$ = 0.0003 M

$[SO^{2-}_{3}]$ = 0.58 - 0.0003

= 0.579 M

Now, we will use $[HSO^{-}_{3}]$ = 0.0003 M

The reaction will be as follows.

$HSO^{2-}_{3} + H_{2}O \rightleftharpoons H_{2}SO_{3} + OH^{-}$

Initial: 0.0003

Equilibrium: 0.0003 - x x x

$K_{b} = \frac{x^{2}}{0.0003 - x}$

$K_{b} = \frac{K_{w}}{K_{a_{1}}}$

= $\frac{10^{-14}}{1.4 \times 10^{-2}}$

= $7.14 \times 10^{-13}$

Therefore, $7.14 \times 10^{-13} = \frac{x^{2}}{0.0003 - x}$

As, x <<<< 0.0003. So, we can neglect x.

Therefore, $x^{2} = 7.14 \times 10^{-13} \times 0.0003$

= $0.00214 \times 10^{-13}$

x = $0.0146 \times 10^{-6}$

x = $[OH^{-}] = [H_{2}SO_{3}]$ = $1.46 \times 10^{-8}$

$[H^{+}] = \frac{10^{-14}}{[OH^{-}]}$

= $\frac{10^{-14}}{0.0003}$

= $3.33 \times 10^{-11}$ M

Thus, we can conclude that the concentration of spectator ion is $3.33 \times 10^{-11}$ M.

5 0

3 years ago