At a constant speed of 5.00 m/s, the speed at which the poodle completes a full revolution is

so that its period is
(where 1 revolution corresponds exactly to 360 degrees). We use this to determine how much of the circular path the poodle traverses in each given time interval with duration
. Denote by
the angle between the velocity vectors (same as the angle subtended by the arc the poodle traverses), then



We can then compute the magnitude of the velocity vector differences
for each time interval by using the law of cosines:


and in turn we find the magnitude of the average acceleration vectors to be

So that takes care of parts A, C, and E. Unfortunately, without knowing the poodle's starting position, it's impossible to tell precisely in what directions each average acceleration vector points.
<span>An electric current.</span>
Answer:
K = .3941 × 10³ W/m.K
Explanation:
Qcond = K A ΔT÷ L
∴K = Qcond ×L ÷ A ΔT
J ÷ S = P
P = I × V =Qcond
∴Qcond = I × V
= 0.6 A × 110 V
=66 W
L = 0.12 m
ΔT = 8 °C
Qcond =33 V
Area = (πD²) ÷ 4
= [π (4 × 10⁻² )²] ÷ 4
= 1.256 × 10⁻³ m²
∴A = 1.256 × 10 ⁻³³ m²
So K = ( Qcond × L ) ÷ A ΔT
= (33) (0.12 ) ÷ (1.256 ×10⁻³ ) × 8
= 0.3941 × 10³ W/m .K
Answer: it is due to friction.
Explanation: if you were to push an object that is at rest, there is static friction that you would first need to overcome. An example would be pushing a car as it is in neutral. Pushing it takes more force and work to overcome that friction.
But once it overcomes static, it will then turn to kinetic friction. Once the car starts to move, you notice that it is easier to push. This is due to the fact that kinetic friction would equal normal force times the constant while the static friction is greater than or equal to the normal force times the constant.
Hope this helps!!!