Answer:<span>Humid air is lighter, so it has lower pressure.
The reason is the molecules of water are H2O, whose molar mass is 18 g/mol.
These molecules displaces molecules of N2 and O2, whose molar masses are:
N2: 2*14g/mol = 28 g/mol, and
O2: 2*16g/mol = 32 g/mol.
Then molecules of 28g/mol and 32 g/mol are being replaced with molecules of 18g/mol, leading to a lower weight of the same volume of air, which results in lower pressure.
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Stephen`s Law:
P = (Sigma) · A · e · T^4
P in = P out
e = 1 for blacktop;
1150 W = (Sigma) · T^4
(Sigma) = 5.669 · 10 ^(-8) W/m²K^4
T^4 = 1150 : ( 5.669 · 10^(-8) )
T^4 = 202.875 · 10^8
T = 3.774 · 10² =
377.4 KAnswer: Equilibrium temperature is 377.4 K.
Answer:
The object will move to Xfinal = 7.5m
Explanation:
By relating the final velocity of the object and its acceleration, I can obtain the time required to reach this velocity point:
Vf= a × t ⇒ t= (7.2 m/s) / (4.2( m/s^2)) = 1,7143 s
With the equation of the total space traveled and the previously determined time I can obtain the end point of the object on the x-axis:
Xfinal= X0 + /1/2) × a × (t^2) = 3.9m + (1/2) × 4.2( m/s^2) × ((1,7143 s) ^2) =
= 3.9m + 3.6m = 7.5m
Answer:
Velocity = 8 ft/s
Acceleration = 0 m/s²
Explanation:
Since, the horse is moving with a constant velocity, whose magnitude is given as equal to 8 ft/s. Therefore, it will have the same velocity when it is 10 ft away from the barn. And the velocity of hay bale will be same as the velocity of horse, as the horse is carrying the bales. Therefore:
<u>Velocity = 8 ft/s</u>
Coming to the second part of the question, which relates to the acceleration of the hay bale, when horse is 10 ft away from the barn. The formula for acceleration is given as:
Acceleration = Change in Velocity/ Time
But, the velocity of the horse in constant, which means there is no change in velocity. Hence,
Change in Velocity = 0
Therefore,
Acceleration = 0/Time
<u>Acceleration 0 m/s²</u>
Answer:
left
Explanation:
N pole should be in the same direction of the field, so N will point left.