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3 years ago

A rubber band that has been stretched has gained ____ energy

Physics

1 answer:

Dafna11 [192]3 years ago

3 0

Answer: potential

Explanation:

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You need to get to class, 300 meters away, and you arrive in 1 minute. What speed were you walking? (calculate in meters per sec

ella [17]

5 meters per second. 300 / 60(seconds)

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2 years ago

What does the change of motion of an object depend on?

IrinaVladis [17]

Answer:

I think the answer is B

Explanation:

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3 years ago

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An eagle flew for 3 hours at 115 km/h and 5 hours at 136 km/h. How far did the eagle fly?

Yanka [14]

Answer:

the eagle flew 1,025 km

Explanation:

since the eagle flew for 3 hours at 115 km/h it flew a total of 345 km during that time. During the 5 hours at 136 km/h the eagle flew a total of 680 km.

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3 years ago

Which ray diagram correctly illustrates what happens when light is incident from the air onto a flat glass surface? The dotted l

prohojiy [21]

Answer:

When light incident at angle more than critical angle then whole beam of light will get reflected at same angle into the same medium

So correct answer is

Option D

Explanation:

Critical angle is the maximum angle of incidence for which light shows the phenomenon of refraction of light

Here light bends at 90 degree angle when light incident at critical angle

Now if the incident light is more than the critical angle then light will follow the rules of reflection and all light rays will get reflected at same angle as that of angle of incidence

So here we can say that correct answer is

Option D

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3 years ago

MAJOR POINTS! Solve the system of equations to find <img src="https://tex.z-dn.net/?f=%20a_%7B2%7D%20%20" id="TexFormula1" title

Monica [59]

You are dealing with pulleys?

can be done with addition of the two equations to eliminate T.

$(2^{*}) \quad {} -m_1 g \cos \theta + T = m_1 a _2$
+
$(4^{*}) \quad 3m_1 g - T = 3m_1 a_2$
=

$(-m_1 g \cos\theta + 3m_1 g) + (T - T) = m_1 a _2 + 3m_1 a_2 \implies \\ \\
(-m_1 g \cos\theta + 3m_1 g) = 4m_1 a_2 \implies \\ \\
m_1(- g \cos\theta + 3g)= 4m_1 a_2$

we can cancel m₁ by dividing both sides by it, assuming mass is not zero

$(- g \cos\theta + 3g)= 4a_2 \implies \\ \\
a_2 = \dfrac{- g \cos\theta + 3g}{4} \\ \\
a_2 = \dfrac{- 9.80 \cos 60 + 3(9.80)}{4} \\ \\
a_2 = 6.125 \text{m/s}^2
$

a₂ = 6.125 m/s² ( do significant digits if you need to)

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3 years ago