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AnnyKZ [126]
3 years ago
12

Can you help me What is love

Chemistry
1 answer:
Elza [17]3 years ago
7 0
Love is the hormones inside you giving u a sense of emotion that comes from your brain
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I’m making a transition from stare n=1 to state n=2 the hydrogen atom must
MatroZZZ [7]

Answer:

Water, 35 liters. Carbon, 20 kilograms. Ammonia, 4 liters. Lime, 1.5 kilograms. Phosphorous, 800 grams. Salt, 250 grams. Saltpeter, 100 grams. Sulfur, 80 grams. Fluorine, seven-point-five. Iron, five. Silicon, three grams. And trace

amounts of 15 other elements.

the ingredients of the average adult,right down to the last specks of protein in your eyelashes. And even though science has given us the entire physical breakdown, there's never been a successful attempt at bringing a human to life. There's still something missing. Something scientists haven't been able to find in centuries of research. ...and in case you're wondering, all those ingredients can be bought on a child's allowance. humans can be made rather cheap. There's no magic to it.

6 0
3 years ago
If the density of a metal bar is 3.47 g/mL and volume is 30 mL, calculate the mass of the metal bar in grams (g). Show the steps
Hitman42 [59]

Answer:

m=104.1g

Explanation:

Hello,

In this case, considering that the density is considered as the quotient of the mass and volume:

\rho =\frac{m}{V}

We can easily compute the mass by solving for it as follows:

m=V*\rho =30 mL*3.47g/mL\\\\m=104.1g

Best regards.

7 0
3 years ago
For the reaction of oxygen and nitrogen to form nitric oxide, consider the following thermodynamic data: ΔH∘rxn 180.5 kJ/mol ΔS∘
nasty-shy [4]

Answer:

7.28 × 10³ K

Explanation:

Let's consider the following reaction.

N₂(g) + O₂(g) → 2 NO(g)

The reaction is spontaneous when the standard Gibbs free energy (ΔG°) is negative. ΔG° is related to the standard enthalpy of the reaction (ΔH°) and the standard entropy of the reaction (ΔS°) through the following expression.

ΔG° = ΔH° - T . ΔS°

If ΔG° < 0,

ΔH° - T . ΔS° < 0

ΔH° < T . ΔS°

T > ΔH°/ΔS° = (180.5 × 10³ J/mol)/(24.8 J/mol.K) = 7.28 × 10³ K

The reaction is spontaneous above 7.28 × 10³ K.

7 0
4 years ago
HEY PLEASE THANK YOU
Goshia [24]
Radon hope this helps.
 
original answer was monoxide which is incorrect and dioxide is incorrect and it is not hydrogen meaning it has to be radon.
5 0
3 years ago
WILL MARK BRAINLIEST
ch4aika [34]

Answer:

hope this helps

Explanation:

it will tell you what you need to know

Download pdf
5 0
3 years ago
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