Answer:
The final temperature of the mixture is 22.3°C
Explanation:
Assuming that the 120 g substance at 80°C is water, final temperature of the mixture can be determined using the formula:
Heat lost = Heat gained
Heat = mc∆T where m is mass, c is specific heat capacity of water, and ∆T is the temperature change =<em> Tfinal - Tinitial</em>.
Let the final temperature be T
Heat lost = 120 × c × (T - 80)
Heat gained = 3000 × c × ( T - 20)
Equating the heat lost and heat gained
120 × c × -(T - 80) = 3000 × c × (T - 20)
9600 - 120T = 3000T - 60000
60000 + 9600 = 3000T + 120T
69600 = 3120T
T = 69600/3120
T = 22.3°C
Therefore, the final temperature of the mixture is 22.3°C
Answer:
the answer is 4 because 3 just have d orbitals
Answer: Rate in terms of disappearance of =
Rate in terms of disappearance of =
Rate in terms of appearance of =
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.
Rate in terms of disappearance of =
Rate in terms of disappearance of =
Rate in terms of appearance of =
<u>Answer:</u> The molar mass of the gas is 35.87 g/mol.
<u>Explanation:</u>
To calculate the mass of gas, we use the equation given by ideal gas:
PV = nRT
or,
where,
P = Pressure of gas = 945 mmHg
V = Volume of the gas = 0.35 L
m = Mass of gas = 0.527 g
M = Molar mass of gas = ? g/mo
R = Gas constant =
T = Temperature of gas =
Putting values in above equation, we get:
Hence, the molar mass of the gas is 35.87 g/mol.