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belka [17]
4 years ago
7

indicate whether the entropy of the system increases or decreases. Mixing 10 mL of 90.0 °C water with 10 mL of 10 °C water. The

answer is that entropy increases. I need the brief explanation why the entropy increases at this situation.
Chemistry
1 answer:
Ivanshal [37]4 years ago
5 0

Answer:

When the water is mixed with water at lower temperature the effective temperature of the system (i.e the water at lower temperature) will increase, thereby increasing it's entropy

Explanation:

The answer that "the entropy will is increases" is correct as:

The water at 90° C i.e at higher temperature is mixed with the water at 10° C i.e the water at the lower temperature.

The water at lower temperature will have molecules with lower energy while the water with higher temperature will have molecules undergoing high thermal collisions. Thereby, when the water is mixed with water at lower temperature the effective temperature of the system (i.e the water at lower temperature) will increase, thereby increasing it's entropy.

Therefore, the answer is correct with respect to the water at lower temperature.

Meanwhile, for the water at higher temperature , the temperature of the system will decrease. Thus, the entropy of the water at higher level will decrease.

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A sample of Ne gas has a pressure of 654 mmHg with an unknown volume. The gas has a pressure of 345 mmHg when the volume is 495m
Lemur [1.5K]

Answer:

The initial volume of Ne gas is 261mL

Explanation:

This question can be answered using Ideal Gas Equation;

However, the following are the given parameters

Initial Pressure = 654mmHg

Finial Pressure = 345mmHg

Final Volume = 495mL

Required

Initial Volume?

The question says that Temperature is constant;

This implies that, we'll make use of Boyle's law ideal gas equation which states;

P_1V_1 = P_2V_2

Where P_1 represent the initial pressure

P_2 represent the final pressure

T_1 represent the initial temperature

T_2 represent the final temperature

P_1 = 654mmHg\\P_2 = 345mmHg\\V_2 = 495mL

Substitute these values in the formula above;

654 * V_1 = 345 * 495

654V_1 = 170775

Divide both sides by 654

\frac{654V_1}{654} = \frac{170775}{654}

V_1 = \frac{170775}{654}

V_1 = 261.123853211

V_1 = 261mL (Approximated)

<em>The initial volume of Ne gas is 261mL</em>

7 0
3 years ago
0.0278, how many significant figures
My name is Ann [436]

Answer:

There are three significant figures

Explanation:

When counting sig figs you don't count the zeros unless it is between a number greater than zero. The two zeros aren't between the greater numbers so there are only 3.

3 0
3 years ago
Define atomic mass unit?​
sveticcg [70]

Atomic mass unit is the standard unit that is used for indicating mass on an atomic or molecular scale

8 0
3 years ago
Read 2 more answers
An air mass usually forms in an area of _____. low pressure because it's stable low pressure because it's unstable high pressure
horsena [70]

Answer: high pressure because it's stable

Explanation:

Air mass is volume of air which has stable temperature, humidity and pressure horizontally. Over time, each air mass acquires properties of the region by residing over same part of a surface.

Areas of low pressure and high pressure occur where there is warm air and cold air respectively. An air mass usually forms over an area of high pressure. Warm air rises up and cold air takes its place. Warm air has low density and low pressure where as cold air has high density and pressure and therefore, sinks to the bottom. This is a stable condition.  The movement of air mass is responsible for maintenance of temperature conditions on Earth.

6 0
3 years ago
(a) Given that Ka for acetic acid is 1.8 X 10^-5 and that for hypochlorous acid is 3.0 X 10^-8, which is the stronger acid? (b)
Gala2k [10]

Answer:

HOAc is stronger acid than HClO

ClO⁻ is stronger conjugate base than OAc⁻

Kb(OAc⁻) = 5.5 x 10⁻¹⁰

Kb(ClO⁻) = 3.3 x 10⁻⁷

Explanation:

Assume 0.10M HOAc => H⁺ + OAc⁻  with Ka = 1.8 x 10⁻⁵

=> [H⁺] = √Ka·[Acid] =√(1.8 x 10⁻⁵)(0.10) M = 1.3 x 10⁻³M H⁺

Assume 0.10M HClO => H⁺ + ClO⁻ with Ka = 3 x 10⁻⁸

=> [H⁺] = √(3 x 10⁻⁸)(0.10)M = 5.47 x 10⁻⁵M H⁺

HOAc delivers more H⁺ than HClO and is more acidic.

Kb = Kw/Ka, Kw = 1 x 10⁻¹⁴

Kb(OAc⁻) = 5.5 x 10⁻¹⁰

Kb(ClO⁻) = 3.3 x 10⁻⁷

4 0
3 years ago
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