Answer is: the freezing point is 1.63°C and boiling point is 82.01°C.<span>.
1) n(</span><span>nonelectrolyte solute) = 0.656 mol.
</span>m(C₆H₆ - benzene) = 869 g ÷ 1000 g/kg.
m(C₆H₆) = 0.869 kg.<span>
b(solution) = n(</span>nonelectrolyte solute) ÷ m(C₆H₆).<span>
b(solution) = 0.656 mol ÷ 0.869 kg.
b(solution) = 0.754 mol/kg.
2) ΔT = Kf(benzene) · b(solution).
ΔT = 5.12°C/m · 0.754 m.
ΔT = 3.865°C.
Tf = 5.50°C - 3.865°C.
Tf = 1.63°C.
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3) ΔTb = Kb(benzene) · b(solution).
ΔTb = 2.53°C/m · 0.754 m.
ΔTb = 1.91°C.
Tb = 80.1°C + 1.91°C.
Tb = 82.01°C.<span>
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Answer:
Because of the existence of isotopes.
<span>Democritus was the first</span>
Answer:
32.00 g. Hope this helps! PLEASE GIVE ME BRAINLIEST!!!!! =)
Answer : The moles of given compound is, 0.064 mole
Explanation : Given,
Mass of given compound = 40 g
Atomic mass of X = 50 amu
Atomic mass of Y = 45 amu
Atomic mass of Z = 10 amu
First we have to calculate the molar mass of given compound.
The given compound formula is, 
Molar mass of = (5 × Atomic mass of X) + (7 × Atomic mass of Y) + (6 × Atomic mass of Z)
Molar mass of = (5 × 50) + (7 × 45) + (6 × 10) = 625 g/mol
Now we have to calculate the moles of given compound.
Thus, the moles of given compound is, 0.064 mole
