Using the answer from the first part, we know that 2.957 moles of bismuth have formed. Moreover, the molar ratio between bismuth and carbon monoxide is:
2 : 3
Using the method of ratios,
2 : 3
2.957 : CO
CO = (3 * 2.957) / 2
CO = 4.4355
4.436 moles of carbon monoxide will be formed
An not sure,, but maybe 24. don't take my word for it
Answer:
photons
Explanation:
Where,
n is the number of photons
h is Plank's constant having value
c is the speed of light having value
is the wavelength of the light
Given that, wavelength = 514 nm = ![514\times 10^{-9}\ m](https://tex.z-dn.net/?f=514%5Ctimes%2010%5E%7B-9%7D%5C%20m)
Energy = 10.0 mJ = 0.01 J ( 1 mJ = 0.001 J )
Applying the values as:-
![\frac{19.878n}{10^{17}\times \:514}=0.01](https://tex.z-dn.net/?f=%5Cfrac%7B19.878n%7D%7B10%5E%7B17%7D%5Ctimes%20%5C%3A514%7D%3D0.01)
photons
Answer:
ΔH = - 272 kJ
Explanation:
We are going to use the fact that Hess law allows us to calculate the enthalpy change of a reaction no matter if the reaction takes place in one step or in several steps. To do this problem we wll add two times the first step to second step as follows:
N2(g) + 3H2(g) → 2NH3(g) ΔH=−92.kJ Multiplying by 2:
2N2(g) + 6H2(g) → 4NH3(g) ΔH=− 184 kK
plus
4NH3(g) + 5O2(g) → 4NO(g) +6H2O(g) ΔH=−905.kJ
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2N2(g) + 6H2(g) + 5O2(g)→ 4NO(g) + 6H2O(g) ΔH = (-184 +(-905 )) kJ
ΔH = -1089 kJ
Notice how the intermediate NH3 cancels out.
As we can see this equation is for the formation of 4 mol NO, and we are asked to calculate the ΔH for the formation of one mol NO:
-1089 kJ/4 mol NO x 1 mol NO = -272 kJ (rounded to nearest kJ)
Answer:
The coefficient is 1
Explanation:
CaO(s) + CO2(g) -> CaCO3(s)
In the balanced equation, the coefficient for CaO is 1
The coefficient represents the number of moles of a compound in the stoichiometry of the reaction