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KengaRu [80]
4 years ago
13

Please answer this question

Physics
1 answer:
sergij07 [2.7K]4 years ago
3 0

Explanation:

m = kg. v=m/s. g=m/s^2. h= m

>>1/2mv^2=mgh

>>1/2mv^2=mgh>> kg*(m/s)^2= kg*m/s^2*m

>>1/2mv^2=mgh>> kg*(m/s)^2= kg*m/s^2*m>>kg m^2/s^2=kg m^2/s^2 the fraction 1/2 won't be able to make any changes to to the dimensional expression of energy i.e half of energy is still energy therefore you can neglect the number .

<u>>>kg m^2/s^2=kg m^2/s^2</u><u> </u>

<u>></u><u>></u><u>J</u>= J

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Does gravity increase or decrease with greater mass???
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Increase

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6 0
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An insulated piston–cylinder device contains 5 l of saturated liquid water at a constant pressure of 150 kpa. an electric resist
Semmy [17]
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 To find the final state, we will use the First Law:
 Q12 = m(h2 - h1) for closed system undergoing a constant pressure process.
 h2 = 1Q2/m + h1 = 2200/4.7483 + 467.11 = 930.43 kJ/kg.
 At P2 = P1 = 150 kPa, this is a saturated mixture.
 hf = 467.11 kJ/kg, hfg = 2226.5 kJ/kg, sf = 1.4336 kJ/kgK, and sfg = 5.7897  kJ/kgK
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8 0
3 years ago
What happens if the value of VOq doubles
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3 years ago
Assuming that the smallest measurable wavelength in an experiment is 0.950 fm , what is the maximum mass of an object traveling
Arada [10]

Answer:

The maximum mass is 2.89x10^{-21}Kg

Explanation:

The wavelength of the electron can be determined by means of the De Broglie equation.

\lambda = \frac{h}{p} (1)

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Where m is the mass and v is the velocity.

Before using equation 2 it is necessary to express the wavelength from femtometers to meters.

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Finally, equation 2 can be used.

m = \frac{6.624x10^{-34} J.s}{(9.5x10^{-16}m)(241m/s)}

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m = \frac{6.624x10^{-34} Kg.m^{2}/s^{2}.s}{(9.5x10^{-16}m)(241m/s)}

m = 2.89x10^{-21}Kg    

Hence, the maximum mass is 2.89x10^{-21}Kg

6 0
3 years ago
Read 2 more answers
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