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Arturiano [62]
3 years ago
12

A mixture of 90.0 grams of CH4 and 10.0 grams of argon has a pressure of 250 torr under conditions of constant temperature and v

olume. The partial pressure of CH4 in tore is?
Chemistry
1 answer:
kicyunya [14]3 years ago
5 0
The partial pressure is 420 blaze it bro
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Identifying Characteristics of the Gas Laws
elixir [45]

Answer:  The image from the question has the correct answers.

Explanation:  

As summarized in the attached table.

8 0
3 years ago
Using the systematic approach for equilibrium problems, calculate the pH of 0.05 M HOCl. Ka= 3.0*10-8 Group of answer choices 3.
SVEN [57.7K]

Answer:

The pH is equal to 4.41

Explanation:

Since HClO is a weak acid, its dissociation in aqueous medium is:

                HClO   ⇄   ClO-  +  H+

start:          0.05            0         0

change       -x               +x       +x

balance     0.05-x         x         x

As it is a weak acid it dissociates very little, in its ClO- and H + ions, so the change is negative, where x is a degree of dissociation.

the acidity constant when equilibrium is reached is equal to:

Ka=\frac{[ClO-]*[H+]}{[HClO]}=\frac{x*x}{0.05-x}=3x10^{-8}

The 0.05-x fraction can be approximated to 0.05, because the ionized fraction (x) is very small, therefore we have:

3x10^{-8}=\frac{x^{2} }{0.05}

clearing the x and calculating its value we have:

x=3.87x10^{-5}=[H+]=[ClO-]

the pH can be calculated by:

pH=-log[H+]=-log[3.87x10^{-5}]=4.41

7 0
4 years ago
A sample of nitrogen gas had a volume of 500. mL, a pressure in its closed container of 740 torr, and a temperature of 25 °C. Wh
iren2701 [21]

Answer:  Thus the new volume of the gas is 530  ml

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas =  740 torr

P_2 = final pressure of gas = 760 torr

V_1 = initial volume of gas = 500 ml

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 25^oC=273+25=298K

T_2 = final temperature of gas = 50^oC=273+50=323K

Now put all the given values in the above equation, we get:

\frac{740\times 500}{298}=\frac{760\times V_2}{323}

V_2=530ml

Thus the new volume of the gas is 530 ml

6 0
3 years ago
Which statement is true for an open system?
Bingel [31]

Answer:

Before we get into the first law of thermodynamics we need to understand the relation between heat and work and the concept of internal energy. Just like mass, energy is always conserved i.e. it can neither be created nor destroyed but it can be transformed from one form to another. Internal energy is a thermodynamic property of the system that refers to the energy associated with the molecules of the system which includes kinetic energy and potential energy.

Whenever a system goes through any change due to interaction of heat, work and internal energy, it is followed by numerous energy transfer and conversions. However, during these transfers, there is no net change in the total energy.

Similarly, if we look at the first law of thermodynamics it affirms that heat is a form of energy. What it means is that the thermodynamic processes are governed by the principle of conservation of energy. The first law of thermodynamics is also sometimes referred to as the Law of Conservation of Energy

Explanation:

3 0
3 years ago
What volume will 145 g of butane occupy at 745 torr and 35 ∘c?
Margaret [11]

First let us compute for the number of moles of butane (molar mass = 58.12 g/mol)

number of moles = 145 g / (58.12 g/mol) = 2.49 mol

<span>We  use the ideal gas equation to calculate the volume:</span>

<span> V = n R T / P</span>

V = 2.49 mol * 62.36367 L torr / mol K * 308.15 K / 745 torr

<span>V = 64.35 L</span>

8 0
3 years ago
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