H₂S
<h3>Further explanation</h3>
Given
ΔH fusion and ΔH vaporization of different substances
Required
The substance absorbs 58.16 kJ of energy when 3.11 mol vaporizes
Solution
We can use the formula :
![\tt \Delta H=\dfrac{Q}{n}](https://tex.z-dn.net/?f=%5Ctt%20%5CDelta%20H%3D%5Cdfrac%7BQ%7D%7Bn%7D)
Q=heat/energy absorbed
n = moles
The heat absorbed : 58.16 kJ
moles = 3.11
so ΔH vaporization :
![\tt \Delta H_{vap}=\dfrac{58.16~kJ}{3.11~mol}\\\\\Delta H_{vap}=18.7~kJ/mol](https://tex.z-dn.net/?f=%5Ctt%20%5CDelta%20H_%7Bvap%7D%3D%5Cdfrac%7B58.16~kJ%7D%7B3.11~mol%7D%5C%5C%5C%5C%5CDelta%20H_%7Bvap%7D%3D18.7~kJ%2Fmol)
The correct substance which has ΔH vaporization = 18.7 kj / mol is H₂S
(H₂S from the data above has ΔH fusion = 2.37 kj / mol and ΔH vaporization = 18.7 kj / mol)
The answer would actually be false. I just took the test.
23. The correct answer would be a (AlPO4 + H2O).
This is an example of a neutralization reaction (an acid and a base react to form water and a salt).
24. a, combination reaction. There are two reactants and one product.
<span>I was correct... 1 is adding more reactant molecules and 2 was decreasing in ch3br concentration over time </span>