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3 years ago

What is the mass spectrom

Chemistry

1 answer:

NARA [144]3 years ago

7 0

Answer:

Here's your Answer

Explanation:

the mass spectrum is the graphical representation of the ion abundance versus the mass to charge of the ions separated in mass spectrometer

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Find the de Broglie wavelength lambda for an electron moving at a speed of 1.00 \times 10^6 \; {\rm m/s}. (Note that this speed

masya89 [10]

(A) $7.28\cdot 10^{-10} m$

The De Broglie wavelength of an electron is given by

$\lambda=\frac{h}{p}$ (1)

where

h is the Planck constant

p is the momentum of the electron

The electron in this problem has a speed of

$v=1.00\cdot 10^6 m/s$

and its mass is

$m=9.11\cdot 10^{-31} kg$

So, its momentum is

$p=mv=(9.11\cdot 10^{-31} kg)(1.00\cdot 10^6 m/s)=9.11\cdot 10^{-25}kg m/s$

And substituting into (1), we find its De Broglie wavelength

$\lambda=\frac{6.63\cdot 10^{-34}Js}{9.11\cdot 10^{-25} kg m/s}=7.28\cdot 10^{-10} m$

(B) $1.16\cdot 10^{-34}m$

In this case we have:

m = 0.143 kg is the mass of the ball

v = 40.0 m/s is the speed of the ball

So, the momentum of the ball is

$p=mv=(0.143 kg)(40.0 m/s)=5.72 kg m/s$

And so, the De Broglie wavelength of the ball is given by

$\lambda=\frac{h}{p}=\frac{6.63\cdot 10^{-34} Js}{5.72 kg m/s}=1.16\cdot 10^{-34}m$

(C) $9.02\cdot 10^{-9}m$

The location of the first intensity minima is given by

$y=\frac{L\lambda}{a}$

where in this case we have

$y=0.492 cm = 4.92\cdot 10^{-3} m$

L = 1.091 is the distance between the detector and the slit

$a=2.00\mu m=2.00\cdot 10^{-6}m$ is the width of the slit

Solving the formula for $\lambda$ , we find the wavelength of the electrons in the beam:

$\lambda=\frac{ya}{L}=\frac{(4.92\cdot 10^{-3}m)(2.00\cdot 10^{-6} m)}{1.091 m}=9.02\cdot 10^{-9}m$

(D) $7.35\cdot 10^{-26}kg m/s$

The momentum of one of these electrons can be found by re-arranging the formula of the De Broglie wavelength:

$p=\frac{h}{\lambda}$

where here we have

$\lambda=9.02\cdot 10^{-9}m$ is the wavelength

Substituting into the formula, we find

$p=\frac{6.63\cdot 10^{-34}Js}{9.02\cdot 10^{-9}m}=7.35\cdot 10^{-26}kg m/s$

7 0

3 years ago

1‑propanol ( n ‑propanol) and 2‑propanol (isopropanol) form ideal solutions in all proportions. Calculate the partial pressure a

Alex777 [14]

Answer:

$y_{prop}$ = 0.134; $y_{iso}$ = 0.866

The partial pressure of isopropanol = 34.04 Torr; The partial pressure of propanol = 5.26 Torr

Explanation:

For each of the solutions:

mole fraction of isopropanol ( $x_{iso}$ ) = 1 - mole fraction of propanol ( $x_{prop}$ ).

Given: mole fraction of propanol = 0.247. Thus, the mole fraction of isopropanol = 1 - 0.247 = 0.753.

Furthermole, the partial pressure of isopropanol = $x_{iso}$ *vapor pressure of isopropanol = 0.753*45.2 Torr = 34.04 Torr

The partial pressure of propanol = $x_{prop}$ *vapor pressure of propanol = 0.247*20.9 Torr = 5.16 Torr

Similarly,

In the vapor phase,

The mole fraction of propanol ( $y_{prop}$ ) = $\frac{P_{prop} }{P_{prop}+P_{iso}}$

Where, $P_{prop}$ is the partial pressure of propanol and $P_{iso}$ is the partial pressure of isopropanol.

Therefore,

$y_{prop}$ = 5.26/(34.04+5.16) = 0.134

$y_{iso}$ = 1 - 0.134 = 0.866

5 0

3 years ago

I need to know number 2 3 4 and 5

dexar [7]

Answer 2: 57.21235000000001

Answer 3: 44.01g

Answer 4: 24.645320000000005

Answer 5: 107.04578240000001

Good luck

7 0

3 years ago

How many total electrons can enter the set of 3p orbitals?<br> a. 3<br> b. 10<br> c. 2<br> d. 6

Sliva [168]

Answer:

For n=3 and l=1=p

It is 3p-orbital.

Magnetic quantum number m

have values from -l to +l and total of 2l+1 values.

Forl=1, m

values are:

=−1,0,1 for l=1; total m

values =3= Number of orbitals

Each orbital can occupy maximum of two electron

Number of electrons =2×3=6

Thus 6 electrons will show same quantum number values of n=3 and l=1.

Number of elements with last electron in 3p orbitals = 6

5 0

3 years ago

Give reason why wood is solid?

VARVARA [1.3K]

Solid wood is a term most commonly used to distinguish between ordinary lumber and engineered wood, but it also refers to structures that do not have hollow spaces. Engineered wood products are manufactured by binding together wood strands, fibers, or veneers with adhesives to form a composite material.

Woof. Hope it helps!!! :) ....Reason*

3 0

3 years ago

Read 2 more answers

What is the mass spectrom​

What is the mass spectrom