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Ostrovityanka [42]
3 years ago
11

What are clouds that form near the ground and look like fluffy heaps of cotton called?

Chemistry
2 answers:
stich3 [128]3 years ago
4 0
There are a few that look like fluffy heaps of cotton. The ones I would assume you're talking about are Cumulus clouds.
Clouds on the ground are called fog.
Lisa [10]3 years ago
4 0
Fog.....I guess.....fog is made when the water vapour (cloud) combines on the surface of the earth...so fog
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Following the instructions in your lab manual, you have titrated a 25.00 mL sample of 0.0100 M KIO3 with a solution of Na2S2O3 o
vivado [14]

<u>Answer:</u>

<u>For 1:</u> The amount of potassium iodate that were titrated is 2.5\times 10^{-4} moles

<u>For 2:</u> The amount of sodium thiosulfate required is 1.25\times 10^{-4} moles

<u>Explanation:</u>

  • <u>For 1:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in L)}}

Molarity of KIO_3 solution = 0.0100 M

Volume of solution = 25 mL

Putting values in above equation, we get:

0.0100M=\frac{\text{Moles of }KIO_3\times 1000}{25}\\\\\text{Moles of }KIO_3=\frac{0.0100\times 25}{1000}=0.00025mol

Hence, the amount of potassium iodate that were titrated is 2.5\times 10^{-4} moles

  • <u>For 2:</u>

The chemical equation for the reaction of potassium iodate and sodium thiosulfate follows:

2KIO_3+Na_2S_2O_3\rightarrow K_2S_2O_3+2NaIO_3

By Stoichiometry of the reaction:

2 moles of potassium iodate reacts with 1 mole of sodium thiosulfate

So, 0.00025 moles of potassium iodate will react with = \frac{1}{2}\times 0.00025=0.000125mol of sodium thiosulfate

Hence, the amount of sodium thiosulfate required is 1.25\times 10^{-4} moles

6 0
3 years ago
An experimenter performs a RICS experiment using a mixture (mixture 1:1 of monomers and tetramers, with a total concentration of
ICE Princess25 [194]

Answer:

Raster Image Correlation Spectroscopy (RICS) is a novel new technique for measuring molecular dynamics and confocal fluorescence imaging concentrations. RICS technique extracts information on molecular dynamics and concentrations of live cell images taken in commercial confocal systems

Explanation:

RICS analysis must be performed on images acquired through raster scanning. Laser scanning microscopes generate images by measuring the fluorescence intensity in one area of ​​a pixel at a time (a 'pixel' in this context does not have the same definition as a pixel in computer graphics, but refers to a measurement of localized intensity). The value of a pixel is obtained by illuminating a region of the sample with the focal volume of a laser beam and measuring the intensity of the fluorescence emitted. The laser beam moves to a new location and a new pixel is recorded. Each pixel can be considered to correspond to a region of the sample, with its width (called pixel size) defined by the distance the beam moves between measurements. This means that the size of a pixel is separate and independent from the size of the focal volume of the laser beam.

4 0
3 years ago
Which of the following statements is true about the composition of the atmosphere?
Phoenix [80]

Answer : Option D) The atmospheric conditions vary as one changes latitude and altitude.

Explanation : The composition of the atmosphere varies according to the latitude and altitude because of the unequal heating of the earth surface at different latitudes and altitudes which results into atmospheric changes. It also creates different regions and zones.

3 0
3 years ago
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What is the epicenter?
hoa [83]

Answer:

basically the middle of an earthquake

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3 years ago
How many moles are in 5.5 x 10-23 molecules of H2O
masha68 [24]

Answer:

0.914moles

Explanation:

The number of moles in a substance can be got by dividing the number of atoms/molecules/particles by Avagadro's constant (6.02 × 10^23).

That is;

number of moles (n) = number of atom (nA) ÷ 6.02 × 10^23

According to this question, there are 5.5 x 10-23 molecules of H2O

n = 5.5 x 10^23 ÷ 6.02 × 10^23

n = 0.914 × 10^(23-23)

n = 0.914 × 10^0

n = 0.914 × 1

n = 0.914moles

6 0
3 years ago
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